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elena-s [515]
3 years ago
12

2) A membership to the local gym costs $40 and then $2 per visit. What is the maximum number of visits that can be made for $90?

Is the function's model linear or exponential? A) 25; linear B) 28; exponential C) 30; linear D) 32; exponential
Mathematics
2 answers:
posledela3 years ago
5 0
A is the correct answer because 90 minus 40 is 50 50 divided by 2 is 25
ra1l [238]3 years ago
5 0
The answer is A/ 25; linear
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Create a four types of two steps each with different operation. Solve them and explain the steps
Luba_88 [7]

Answer:

4 + 5 = 9

9 – 5 = 4

9 – 5 ≠ 5 – 9

9 – 4 = 9 + (–4)

6 0
3 years ago
You are in charge of purchases at the student-run used-book supply program at your college, and you must decide how many introdu
mariarad [96]

Answer:

  • Calculus texts: 600
  • History texts: 0
  • Marketing texts: 0

Step-by-step explanation:

Each Calculus text returns $10/2 = $5 per unit of shelf space. For History and Marketing texts, the respective numbers are $4/1 = $4 per unit, and $8/4 = $2 per unit. Using 1200 units of shelf space for 600 Calculus texts returns ...

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Any other use of units of shelf space will reduce profit.

7 0
3 years ago
30,000 is how many times as much as 30
jekas [21]
The answer is 1,000 if you think about 30*1,000=30,000
8 0
3 years ago
What is the slope of the equation?<br><br> y = 2x - 3
PolarNik [594]

Answer:

2

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Consider the equation below.
Korvikt [17]

Answer:

Equation in square form:

y=3(x+5)^2-4

Extreme value:

(h,k)=(-5,-4)

Step-by-step explanation:

We are given

y=3x^2+30x+71

we can complete square

y=3(x^2+10x)+71

we can use formula

a^2+2ab+b^2=(a+b)^2

y=3(x^2+2\times x\times 5)+71

now, we can add and subtract 5^2

y=3(x^2+2\times x\times 5+5^2-5^2)+71

y=3(x^2+2\times x\times 5+5^2)-3\times 5^2+71

y=3(x+5)^2-75+71

So, we get equation as

y=3(x+5)^2-4

Extreme values:

we know that this parabola

and vertex of parabola always at extreme values

so, we can compare it with

y=a(x-h)^2+k

where

vertex=(h,k)

now, we can compare and find h and k

y=3(x+5)^2-4

we get

h=-5

k=-4

so, extreme value of this equation is

(h,k)=(-5,-4)

6 0
3 years ago
Read 2 more answers
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