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SVETLANKA909090 [29]
3 years ago
7

A tank holds 50% of a mixture of acid in water that is 30% acid if 20 gallons of gas are added to the mixture what is the percen

t of acid in the mixture
Mathematics
1 answer:
ehidna [41]3 years ago
3 0
Parts per whole: 50(.30) + 20 is the part that is acid 50 + 20
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A ↔ B ↔ C ↔ D ↔ E ↔ F

 \frac{1}{4} AD      8      7      \frac{4}{5} AD   ???

AB + BC + CD = AD   <em>segment addition postulate</em>

\frac{1}{4} AD   +   8   +   7   = AD

\frac{1}{4} AD   +       15        = AD

AD         + 60    = 4AD

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AB =  \frac{1}{4} AD    =  \frac{1}{4}(20)    = 5

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Answer: 11 + EF

Note: You did not provide any info about EF.  If you have additional information that you did not type in, calculate EF and add it to 11 to find the length of CF.

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