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Whitepunk [10]
3 years ago
9

One fifth the sum of one half and one third

Mathematics
2 answers:
skelet666 [1.2K]3 years ago
8 0
Rewrite the equation as
1/5 * (1/2 + 1/3)
We must first solve the stuff inside the parentheses, to do this we must find a common denominator, in this case 6

1/2 becomes 3/6 and 1/3 becomes 2/6 thus (1/2 + 1/3) = (3/6 + 2/6) = (5/6)
Now we can multiple (1/5)*(5/6) you can cancel out the 5's and then you are left with you answer
1/6
Juliette [100K]3 years ago
3 0
1/5( 1/2 + 1/3)
1/5 (3/6 + 2/6)
1/5(5/6)
5/30
1/6
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A particular Spotify playlist contains 105 songs, of which 10 are by the Beatles. Suppose the shuffle feature is used to play th
katovenus [111]

Answer: The required probability is 0.3296.

Step-by-step explanation:

Since we have given that

Number of songs = 105

Number of songs are by the Beatles = 10

So, Number of songs are not by the Beatles = 105-10=95

So, the probability that the first Beatles song heard is the fifth song played is given by

\dfrac{^{95}C_4\times ^{10}C_1}{^{105}C_5}\\\\=0.3296

Hence, the required probability is 0.3296.

8 0
3 years ago
Mrs. Smith's class is working on a variety of science experiments. Each
SVETLANKA909090 [29]

Answer:

66

Step-by-step explanation:

If there are  <em>n</em>  students, then the number of pairs is \frac{n(n-1)}{2}.

With 12 students, \frac{12(12-1)}{2} = \frac{132}{2}=66 pairs can be formed.

The reason the formula works is this:  Each of the 12 students can be paired with 11 other students (no student is paired with him/her self).  But counting 12 x 11 = 132  counts each pair <u>twice</u>.  Example: student A can be paired with student B,..., student B can be paired with student A.  The pair was counted two times.

See the attached image that shows pairings of 5 students.  There are

5(5 - 1)/2 = 5(4)/2 = 10 pairs.

8 0
3 years ago
Explain how you use estimation to check the reasonableness of a solution to a practical problem.
Oxana [17]

Answer:

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Step-by-step explanation:

3 0
3 years ago
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SSS

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3 years ago
Factor this trinomial. Your answer should consist of two binomials.
Sergeu [11.5K]
Y² + 8y - 33 :

Break  the expression  into groups for formula ax²+ bx+c :

= (y²- 3y) + (11y - 33 )

Factor y from y² - 3y =>  y (y - 3)

Factor out 11 from  11 y - 33 => 11 (y - 3)

= y ( y- 3 ) + 11 ( y - 3 )

Factor  out common  term (y - 3 ) :

= ( y - 3 ) ( y + 11 )

hope this helps!




5 0
3 years ago
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