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STALIN [3.7K]
2 years ago
11

The scatter plot below shows the algebra grades and the number of absences of different students for the first semester. Which o

f the following is the best interpretation of this scatter plot?
A. As the number of absences increase, the algebra grade stays the same.
B. Students who have fewer absences seem to have higher algebra grades.
C. Students who have the most absences seem to have higher algebra grades.
D. As the number of absences decrease, algebra grades stay the same.

Mathematics
2 answers:
swat322 years ago
6 0

Answer:

Look up on youtbe

Step-by-step explanation:

It will give you A direct answer and you would actualy learn the subject

sweet [91]2 years ago
3 0
So beleive the answer would be C i hope i’m right
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Solve for each expression by writing the solution in unit form and in standard form.
Sonja [21]

Answer:

<em>Unit Form:</em>

  • <em>3 hundreds, 0 tens, 0 ones</em>
  • <em>5 thousands, 0 hundreds, 0 tens, 0 ones</em>
  • <em>9 thousands, 0 hundreds, 0 tens, 0 ones</em>
  • <em>7 ten thousands, 0 thousands, 0 hundreds, 0 tens, 0 ones</em>

<em>Standard Form:</em>

  • <em>300</em>
  • <em>5,000</em>
  • <em>9,000</em>
  • <em>70,000</em>

Step-by-step explanation:

Here is how to write solutions to expressions in unit form:

Its important to note that unit form expands a standard form number into ones, tens, hundreds, and so on.

Take your first expression for example.

10 × 3 tens

Re-write this expression so that all terms are in standard form. The second term is <em>3 tens,</em> which can be represented as thirty.

10 × 3 tens

10 × 30

Solve this expression. Multiply ten by thirty.

10 × 30

300

The expression is now represented in its simplest form. We can start to write it in unit form. Break up three hundred into its hundreds, tens, and ones.

300

3 hundreds, 00

3 hundreds, 0 tens, 0

3 hundreds, 0 tens, 0 ones

This shows that the solution to the first expression written in unit form is <em>3 hundreds, 0 tens, 0 ones.</em>

We can continue to solve the following expressions in the same manner. Just in case you still need some help. Here is how you find the remaining three solutions in unit form.

<em>Problem Two</em>

5 hundreds × 10

500 × 10

5,000

<em>5 thousands, 0 hundreds, 0 tens, 0 ones</em>

<em>Problem Three</em>

9 ten thousands ÷ 10

90,000 ÷ 10

9,000

<em>9 thousands, 0 hundreds, 0 tens, 0 ones</em>

<em>Problem Four</em>

10 × 7 thousands

10 × 7,000

70,000

<em>7 ten thousands, 0 thousands, 0 hundreds, 0 tens, 0 ones</em>

Here's how to solve the second part of the problem:

This portion says we need to write the solution in standard form. It is important to remember that a number written in standard form will looks like an ordinary number, i.e. 76, 902, 474.

This means that under the category titled '<em>standard form'</em> we must write the answer as the ordinary solution.

8 0
3 years ago
If x is the product of the integers from 1 to 150, inclusive, and 5^y is a factor of x, what is the greatest possible value of y
Maslowich

ANSWER: A) 30

5×30=150 which is the highest number you can go to

5 0
3 years ago
Suppose you have a $60,000 loan with an annual percentage rate of 8% for 25 years.
amid [387]

Answer:

The amount will be more by $30000 in the second loan.

Step-by-step explanation:

The loan of $60000 with APR 8% and for 25 years will grow to 60000 ( 1 + \frac{8 \times 25}{100} ) = 180000 dollars

So, I have to pay $180000 after 25 years.

Now, if we add $100 per month to this final amount then I have to pay $(180000 + 100 × 25 × 12) = $210000

Therefore, the loan amount will be more by $30000 in the second loan. (Answer)  

6 0
3 years ago
Find the area of this parallelogram.
TiliK225 [7]
Hello!

To find the area of a parallelogram you do

bh

b stands for base and h stands for height

10 * 17 = 170

The answer is 170

Hope this helps!
8 0
3 years ago
Someone pls help, its on trig ratios.
Mars2501 [29]

Answer:

BC=12.8,\\AC=15.1

Step-by-step explanation:

In right triangles only, the tangent of an angle is equal to its opposite side divided by its adjacent side.

Therefore, we have the following equation:

\tan 58^{\circ}=\frac{BC}{8}

Solving, we get:

BC=8\tan 58^{\circ}\approx \boxed{12.8}

Also in right triangles only, the cosine of an angle is equal to its adjacent side divided by the hypotenuse of the triangle.

\cos 58^{\circ}=\frac{8}{AC},\\AC=\frac{8}{\cos 58^{\circ}},\\AC\approx \boxed{15.1}

We can also use the Pythagorean theorem now that we've found BC. However, if you choose to do so, make sure you don't use a rounded value for BC, as that could cause a notable deviation in your final answer.

Using the Pythagorean theorem to verify our answers:

8^2+(8\tan 58^{\circ})^2=\left(\frac{8}{\cos 58^{\circ}}\right)^2\:\checkmark

6 0
2 years ago
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