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4 years ago

How would u find the answer idk if they would still be the same and you just have to find that one missing angle?

Mathematics

1 answer:

ivolga24 [154]4 years ago

8 0

Well... with the information you are given you just have to assume they are congruent triangles. The first picture looks like a right triangle, but the angle is 100 not 90... so it wouldn't actually look like that.

So for the missing angle all you do is 180= 100+ 55 + x

x=25

Then just match up the angles with the other triangle, they would be the same. K with F, J with G, and so on

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From the 9 male and 8 female sales representatives for an insurance company, a team of 4 men and 3 women will be selected to at

inessss [21]

Select 4 from 9, and 3 from 8. Multiply together.
C(9,4)*C(8,3)
=9!/(4!5!) * 8!/(3!5!)
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3 0

3 years ago

Please Help. ASAP!!

Ratling [72]

Answer:

Equation: x + (x+ 1) = 67

Step-by-step explanation:

We want to find two consecutive integers.

Let them be labeled as x and x + 1

We want x + (x + 1) = 67

x is the smaller number

x + 1 is the largest

We can solve for x.

x + (x + 1) = 2x + 1 = 67

2x = 66

x = 33

The largest integer is 34

3 0

3 years ago

The length of a rectangle is 6 more than twice the width. if the area is 40 cm^2, find the length and breadth of the rectangle

ra1l [238]

Answer: 3.217 & 12.434

Step-by-step explanation:

If we use w to represent the width, the length will be 6 more than 2 times w.

Hence, the length is $2w+6$ .

The area of a rectangle would be its length times its width, so let's make an equation to represent it's area.

$A=w(2w+6)$

We can also substitute 40 in for A as it's given in the question.

$40 = w(2w+6)$

Distributing w by multiplying it by both terms in the parentheses, we get

$40 = 2w^2+6w$

We can make the equation simpler by dividing both sides by 2.

$20 = w^2+3w$

Subtracting both sides by 20 will make the left-hand side 0.

$0=w^2+3w-20$

Now that we have put this quadratic equation into standard form (ax²+bx+c), we can find its solutions using the quadratic formula.

For reference, the quadratic formula is

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

In this case, a is 1, b is 3, and c is -20.

Substituting, we get

$w=\frac{-3\pm\sqrt{3^2-4(1)(-20)}}{2(1)}$

$w= \frac{-3\pm\sqrt{9+80}}{2}$

$w=\frac{-3+\sqrt{89}}{2}\hspace{0.1cm}or\hspace{0.1cm}\frac{-3-\sqrt{89}}{2}$

Since the second solution results in a negative number, it cannot be the length of w.

$w=\frac{-3+\sqrt{89}}{2}\approx3.217$

The width/breadth of the rectangle is 3.217 cm.

To calculate the length, let's substitute the width into the expression for the length:

$l=2(3.217)+6$

$l=12.434$

The length of this rectangle is 12.434 cm.

6 0

2 years ago

In january of one winter, 3/10 of a wood pile was used in a wood stove. In February, 2/5 of the wood pile was used. What part of

arsen [322]

2/5 is equivalent to 4/10 so at the end of February 4/10 was used up
And at the end of January, 3/10 was used
so 4/10 + 3/10 = 7/10

At the end of February, 7/10 of the wood was used

6 0

3 years ago

A. 2x^2 + 7x + 6

Alexandra [31]

Answer:

Step-by-step explanation:

the 3 equation can not be factorised. Because they will result to fraction

7 0

3 years ago