Answer:
From a <u>table</u>, for an ordered pair (0, y), <em>y</em> will not be <u>zero</u>. From a <u>graph</u>, the y-intercept will not be <u>zero</u>. From an equation, it will have the form, y = mx + b where b is <u>≠ 0</u>.
Step-by-step explanation:
- From a <u>table</u>, for an ordered pair (0, y), <em>y</em> will not be <u>zero</u>. If there is not a constant rate of change in the data displayed in a table, then the table represents a nonlinear nonproportional relationship.
- From a <u>graph</u>, the y-intercept will not be <u>zero</u>. This means that it doesn't contain or go through the origin.
- From an equation, it will have the form, y = mx + b where b is <u>≠ 0.</u> (not equal to zero). If an equation is not a linear equation, it represents a nonproportional relationship. A <u>linear equation</u> of the form y = mx + b may represent either a <em>proportional</em> (b = 0) or <em>nonproportional</em> (b ≠ 0) relationship. Therefore, when b ≠ 0, the relationship between <em>x</em> and <em>y</em> is <u>nonproportional</u>.
Answer:
(2,0)
Step-by-step explanation:
Simply plug in the coordinates. y= 3x - 6, so in this case 0= 3(2) - 6 or 0=0, making the point on the line. If the equation is not true like when using (0,3) and getting 3= -6, then the point is not on the line.
Step-by-step explanation:
×2+(y+3) 2=49
2×y=2y=2×3=6
49-2=47
2y=47-6=41
2y=41÷2=20 1/2
K^(-4) or 1/k^4 (Those are two different ways to write the same answer)
To do this problem you would need to have at least one side length AND the hypotenuse to figure out the other side length.