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Andru [333]
3 years ago
7

There are approximately 3.2 x 10^7 mosquitoes near each backyard pool. How many total mosquitoes are thre in a city with 6.7 x 1

0^12 pools?
PLEASE ANSWER
Mathematics
1 answer:
dexar [7]3 years ago
3 0

Answer:

Step-by-step explanation:

Alright, lets get started.

There are approximately 3.2 \times 10^7 mosquitoes near each backyard pool.

The city has total number of pools 6.7 \times 10^{12}.

So the total mosquitoes will be : 3.2 \times10^7 \times6.7\times 10^{12}

So the total mosquitoes will be : 21.44 \times 10^{19}

So the total mosquitoes will be : 2.144 \times 10^{20}  :   Answer

Hope it will help :)

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a rectangle has a length if x + 7 centimeters. The perimeter of the rectangle is 23 centimeter. What is the value of x
Tems11 [23]

23 = 14 + 2x
reasoning \: for \: each \: term \: in \: the  \\ \: above \: equation\\  \\ p = 23 \\  14 = 7 \times 2 \\ 2x = 2 \times x
\:  \:  \:  \:  \: 23 - 14 \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: 14 + 2x - 14 \\  \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  9 = 2x
\:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: 9  \div 2 \:  \:  \:  \:  \:  \:  \:  \:  \: 2x \div 2 \\  \\   \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: 4.5 = x
So, the answer is 4.5
8 0
3 years ago
If m = 22 and n = 3, what is the value of the following expression? m - 5 • n + 3 A. 51 B. 10 C. 4 D. 54
melisa1 [442]

The answer is B, 10.


Step-by-step explanation: You plug in the values where the variables are, then follow PEMDAS, beginning with 5 times 3.


4 0
3 years ago
If Carl, Steve and John have 40 sweets to share and John gets the most out of all three. What’s the smallest amount he can get?
Basile [38]

Answer:

13 +13 +14 ensures he is getting the smallest amount so its 14

Step-by-step explanation:

6 0
3 years ago
Type the correct answer in the box. Round your answer to the nearest integer.
umka21 [38]

Answer:

m∠ADC = 132°

Step-by-step explanation:

From the figure attached,

By applying sine rule in ΔABD,

\frac{\text{sin}(\angle ABD)}{\text{AD}}=\frac{\text{sin}(\angle ADB)}{AB}

\frac{\text{sin}(120)}{35}=\frac{\text{sin}(\angle ADB)}{30}

sin(∠ADB) = \frac{30\text{sin}(120)}{35}

                 = 0.74231

m∠ADB = \text{sin}^{-1}(0.74231)

             = 47.92°

             ≈ 48°

m∠ADC + m∠ADB = 180° [Linear pair of angles]

m∠ADC + 48° = 180°

m∠ADC = 180° - 48°

m∠ADC = 132°

4 0
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photoshop1234 [79]
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Hope this helps~


4 0
3 years ago
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