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Korvikt [17]
2 years ago
6

The average movie ticket price in dollars since 1980 can be modeled by 0.142x + 1.93 where x is the number of years since 1980.

What values of x would you use to find the average movie ticket price in 1985, 1999, and 2010? Find the ticket prices for each of those years rounded to the nearest cent. Submit your x-values, ticket prices, and all solution steps to earn full credit.
Mathematics
1 answer:
ipn [44]2 years ago
4 0

Answer:

Step-by-step explanation:

1985:

x = 5 years  ( 1980 to 1985- 5 years)

0.142x + 1.93 = 0.142*5 + 1.93

                     = 0.71 + 1.93

                     = $ 2.64

                     

1999:

x = 19 years

0.142x + 1.93 = 0.142*19+ 1.93

                     = 2.698 + 1.93

                     =4.628 =  $ 4.63

                     

2010:

x = 30 years

0.142x + 1.93 = 0.142*30 + 1.93

                     =  4.26 + 1.93

                     = $ 6.19

                   

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Vilka [71]

Answer: The book costs $10 and the pen costs $4✔️

Step-by-step explanation:

Let B the cost of the book and let P the cost of the pen.

Then we know:

The book and the pen cost $14:

B + P = $14 } Equation 1  

We also know:  

The cost of the book is two dollars more than twice the cost of the pen.

B = 2P + $2 } Equation 2  

Now we can substitute the value of B from the equation 2 in the equation 1:

2P + $2 + P = $14

3P = $14 - $2 = $12

P = $12/3 = $4 , cost of the pen

Since we know the value of B from the equation 2, we can calculate B:

B = 2P + $2 = 2x$4 + $2 = $8 + $2 = $10 , cost of the book

Answer: The book costs $10 and the pen costs $4✔️

<h3>Verify </h3>

We can substitute these values in equations 1 and 2 and check the results:

B + P = $14 } Equation 1

$10 + $4 = $14 ✔️check!

B = 2P + $2 } Equation 2  

$10 = 2x$4 + $2 = $8 + $2 = $10 ✔️check!

<h2><em>Spymore</em></h2>
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