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3 years ago

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Harrison ordered 6 cases of pickles for his restaurants. Each case contained p jars of pickles. Harrison delivered an equal numb

er of jars to each of his 7 restaurants. Which expression represents the number of jars of pickles that each restaurant received? A. 6p-7 B. $\frac{6p}{7}$ C. 6p+7 D. 7(6+p) E. $\frac{6}{7p}$

2 answers:

kobusy [5.1K]3 years ago

6 0

Answer: b 6p/7

Step-by-step explanation: 6p = the total amount of pickles. The problem says that he distributes them evenly to 7 restaurants, so that's dividing. So your answer is 6p/7.

kogti [31]3 years ago

3 0

Answer:

B. 6p/7

Step-by-step explanation:

6p = the total amount of pickles

The problem says that he distributes them evenly to 7 restaurants, so that's dividing.

So your answer is 6p/7

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Rhonda had $300 to buy supplies for the animal shelter. She bought 8 bags of dog food and 11 leashes. Each bag of food cost $25.

Readme [11.4K]

Answer:

47.33

Step-by-step explanation:

Hey there! I'm happy to help!

We have 8 bags of dog food and each costs $25.19

8(25.19)=201.52

And we have 11 leashes each costing $4.65.

11(4.65)=51.15

We add these totals up.

201.52+51.15=252.67

We subtract this from 300 to see how much is left.

300-252.67=47.33

Rhonda had $47.33 left after her purchases.

Have a wonderful day! :D

3 0

3 years ago

Need help with these math questions

PSYCHO15rus [73]

$\sqrt{16-x}$ x = 8

Since x = 8, you can plug in/substitute 8 for "x" in the equation:

$\sqrt{16-x}$

$\sqrt{16-8}$

$\sqrt{8}$

2.82842

2.83 You answer is the 4th option

$\sqrt{x+7}$ x = 9

Plug in 9 for "x" in the equation

$\sqrt{x+7}$

$\sqrt{9+7}$

$\sqrt{16}$

4 Your answer is the 1st option

4 0

3 years ago

Perform the indicated operation. Be sure the answer is reduced.

avanturin [10]

<h3>Given Equation:-</h3>

$\boxed{ \rm \frac{4x^{2}y^{3}z}{9} \times \frac{45y}{8 {x}^{5} {z}^{5} }}$

<h3>Step by step expansion:</h3>

$\dashrightarrow \sf\dfrac{4x^{2}y^{3}z}{9} \times \dfrac{45y}{8 {x}^{5} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{ \cancel4x^{2}y^{3}z}{9} \times \dfrac{45y}{ \cancel8 {x}^{5} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{x^{2}y^{3}z}{9} \times \dfrac{45y}{2{x}^{5} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{x^{2}y^{3}z}{ \cancel9} \times \dfrac{ \cancel{45}y}{2{x}^{5} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{x^{2}y^{3}z}{1} \times \dfrac{5y}{2{x}^{5} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{x^{0}y^{3}z}{1} \times \dfrac{5y}{2{x}^{5 - 2} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{y^{3}z}{1} \times \dfrac{5y}{2{x}^{3} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{y^{3}z {}^{0} }{1} \times \dfrac{5y}{2{x}^{3} {z}^{3 - 1} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{y^{3}}{1} \times \dfrac{5y}{2{x}^{3} {z}^{2} }$

$\\ \\$

$\dashrightarrow \sf \dfrac{5y \times {y}^{3} }{2{x}^{3} {z}^{2} }$

$\\ \\$

$\dashrightarrow \sf \dfrac{5y {}^{0} \times {y}^{3 + 1} }{2{x}^{3} {z}^{2} }$

$\\ \\$

$\dashrightarrow \sf \dfrac{5 \times {y}^{4} }{2{x}^{3} {z}^{2} }$

$\\ \\$

$\dashrightarrow \bf \dfrac{5 {y}^{4} }{2{x}^{3} {z}^{2} }$

$\\ \\$

$\therefore \underline{ \textbf{ \textsf{option \red c \: is \: correct}}}$

8 0

2 years ago

Andrew pays a monthly membership fee of $10 at his gym. Each time he uses the gym, he pays $5. Last month, Andrew spent a total

Grace [21]

11
If you replace the x with 11, the new equation would be 10+5(11)=65. First, multiply 5 and 11, your answer would be 55, then add the ten, you would get 65. Which makes the equation true, because 65=65.
I hope this helps
If you have any questions on my answer please feel free to ask :)

3 0

3 years ago

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What does a negative net worth indicate?

Sati [7]

It seems to me that the answer is c!<3

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3 years ago