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Rama09 [41]
3 years ago
12

A set of data with a mean of 45 and a standard deviation of 8.3 is normally distributed. find the value that is +3 standard devi

ations away from the mean. 48.0 78.9 20.1 69.9
Mathematics
2 answers:
lidiya [134]3 years ago
3 0
69.9 is exactly 3 standard deviations away, which means that 78.9 is +3 (more than 3) standard deviations

So the answer is 78.9
Simora [160]3 years ago
3 0

Answer:

D. 69.9

Step-by-step explanation:

We have been given that a set of data with a mean of 45 and a standard deviation of 8.3 is normally distributed. We are asked to find the value that is +3 standard deviations away from the mean.

To find the value that is 3 standard deviation away from mean, we will multiply 3 by standard deviation and ad the result to mean.

45+(3\times 8.3)

45+24.9

69.9

Therefore, 69.9 is 3 standard deviation away from mean of or given data set and option D is the correct choice.

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tatyana61 [14]

f(x)=\left(\dfrac{1}{2}\right)^x\\\\for\ x=-3\to y=\left(\dfrac{1}{2}\right)^{-3}=2^3=8\to(-3,\ 8)\\\\for\ x=-2\to y=\left(\dfrac{1}{2}\right)^{-2}=2^2=4\to(-2,\ 4)\\\\for\ x=-1\to y=\left(\dfrac{1}{2}\right)^{-1}=2^1=2\to(-1,\ 2)\\\\for\ x=0\to y=\left(\dfrac{1}{2}\right)^0=1\to(0,\ 1)\\\\for\ x=1\to y=\left(\dfrac{1}{2}\right)^1=\dfrac{1}{2}\to\left(1,\ \dfrac{1}{2}\right)\\\\for\ x=2\to y=\left(\dfrac{1}{2}\right)^2=\dfrac{1}{4}

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3 years ago
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