Answer:
The answer is given below
Step-by-step explanation:
The loads in the circuit are continuous duty, so the circuit can only loaded to 80% of its current rating.
Calculate 80% current rating of the circuit breaker.
Icb = [ 80/100] (20 A)
= (O.8) (20 A )
= 16 A
Now we assume that the value of supply voltage is 120 V
Now we will calculate current flows via under water light which will be taken as Load 1
<em>Ii = </em>500 W/120 V
= 4.167 A
Current via the circulating pump which will be taken as Load 2 IS 8.5 A
<em>I = </em>load1 + load 2
<em> = 4.167 A + 8.5 A</em>
<em> = 12.67 A</em>
The total current in the circuit obtained which is less than the circuit breaker rating current. Therefore, the power can be operated for both the loads.
Answer:
1/4
Step-by-step explanation:
The ratio of the areas is the square of the ratio of the lengths of sides.
(1/2)² = 1/4
Answer: 1/4
Answer:
Area of model pond = 45.6 inch² (Approx.)
Step-by-step explanation:
Given:
Circumference of circular pond = 24 inches
Find:
Area of model pond
Computation:
Circumference of circle = 2πr
Circumference of circular pond = 2πr
24 = 2[22/7][r]
Radius r = [24 x 7] / [2 x 22]
Radius r = 3.81 inch (Approx.)
Area of circle = πr²
Area of model pond = πr²
Area of model pond = (22/7)(3.81)²
Area of model pond = [3.1428][14.5161]
Area of model pond = 45.6 inch² (Approx.)
