PLEASE HELP ME WITH THIS QUESTION

What is the value of 3 ^ -3

mestny [16]

Answer:

$\frac{1}{27}$

Step-by-step explanation:

$3^{-3}\\=\frac{1}{3}^{3}\\=\frac{1}{27}$

5 0

3 years ago

Use < >, or = to compare the following decimals.

Contact [7]

Answer:

0.32, 0.45, 0.76.

Step-by-step explanation:

so first you would use your < >,= signs and compare all of them until you have eliminated ALL but one (so 0.91<0.98 this is because 0.98 is close to 1 whole than 0.91) and you would continue this explanation for so on

4 0

2 years ago

Solve the equation. 4n−18=52

Margaret [11]

How to solve this: (in case you need it)
4n-18=52
4n-18+18=52+18
4n=70
4n/4=70/4
n=35/2

6 0

3 years ago

Read 2 more answers

A quality analyst of a tennis racquet manufacturing plant investigates if the length of a junior's tennis racquet conforms to th

Burka [1]

Answer:

Confidence interval : $21.506$ to $24.493$

Step-by-step explanation:

A quality analyst selects twenty racquets and obtains the following lengths:

21, 25, 23, 22, 24, 21, 25, 21, 23, 26, 21, 24, 22, 24, 23, 21, 21, 26, 23, 24

So, sample size = n =20

Now we are supposed to find Construct a 99.9% confidence interval for the mean length of all the junior's tennis racquets manufactured at this plant.

Since n < 30

So we will use t-distribution

Confidence level = 99.9%

Significance level = α = 0.001

Now calculate the sample mean

X=21, 25, 23, 22, 24, 21, 25, 21, 23, 26, 21, 24, 22, 24, 23, 21, 21, 26, 23, 24

Sample mean = $\bar{x}=\frac{\sum x}{n}$

Sample mean = $\bar{x}=\frac{21+25+23+22+24+21+25+21+23+ 26+ 21+24+22+ 24+23+21+ 21+ 26+23+ 24}{20}$

Sample mean = $\bar{x}=23$

Sample standard deviation = $\sqrt{\frac{\sum(x-\bar{x})^2}{n-1}}$

Sample standard deviation = $\sqrt{\frac{(21-23)^2+(25-23)^2+(23-23)^2+(22-23)^2+(24-23)^2+(21-23)^2+(25-23)^2+(21-23)^2+(23-23)^2+(26-23)^2+(21-23)^2+(24-23)^2+(22-23)^2+(24-23)^2+(23-23)^2+(21-23)^2+(21-23)^2+(26-23)^2+(23-23)^2+(24-23)^2}{20-1}}$

Sample standard deviation= s = $1.72$

Degree of freedom = n-1 = 20-1 -19

Critical value of t using the t-distribution table $t_{\frac{\alpha}{2}$ = 3.883

Formula of confidence interval : $\bar{x} \pm t_{\frac{\alpha}{2}} \times \frac{s}{\sqrt{n}}$

Substitute the values in the formula

Confidence interval : $23 \pm 1.73 \times \frac{1.72}{\sqrt{20}}$

Confidence interval : $23 -3.883 \times \frac{1.72}{\sqrt{20}}$ to $23 + 3.883 \times \frac{1.72}{\sqrt{20}}$

Confidence interval : $21.506$ to $24.493$

Hence Confidence interval : $21.506$ to $24.493$

3 0

3 years ago

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What are the roots of the polynomial equation x3-7x=6x-12?

Ilia_Sergeevich [38]

This is not a polynomial equation unless one of those is squared. As it stands x=-.833. If you can tell me which is squared I can help solve the polynomial.

Ok, that is usually notated as x^3 to be clear. I'll solve it now.

x^3-13x-12=0

Then use factor theorum to solve x^3-13x-12/x+1 =0
So you get one solution of x+1=0
x=-1

Then you have x^2-x-12 now you complete the square.

Take half of the x-term coefficient and square it. Add this value to both sides. In this example we have:

The x-term coefficient = −1

The half of the x-term coefficient = −1/2

After squaring we have (−1/2)2=1/4

When we add 1/4 to both sides we have:

x2−x+1/4=12+1/4

STEP 3: Simplify right side

x2−x+1/4=49/4

STEP 4: Write the perfect square on the left.

(x−1/2)2=49/4

STEP 5: Take the square root of both sides.

x−1/2=±√49/4

STEP 6: Solve for x.

x=1/2±√49/4

that is,

x1=−3

x2=4

and the one from before

x=-1

7 0

3 years ago

Read 2 more answers

PLEASE HELP ME WITH THIS QUESTION ​

PLEASE HELP ME WITH THIS QUESTION