Now , For 12n to end with 0, it should have 2 as well as 5 in its Prime factors to end with 0, Also to end with 5 , it requires at least a single multiple of 5 in its Prime Factors, So 12n cannot end with the digit 0 or 5.
It has rotational symmetry of order 3 about the centroid of any triangle. Turning the pattern 120° gives you the same pattern.
Answer:
line plots do you mean number line, cos no pic is attached
Number: n
square of number: n^2
sum of n and n^2 is n+n^2=20
Rewriting this equation, we get n^2+n-20=0 = (n+5)(n-4) = 0
Then n+5=0 and n-4=0, so n = -5 and n = 4.
You must check both results. It could happen that both are correct, or that only one is correct.
