Try this option:
1. if 8*x²+b*x+3=8*x²+p*x+q*x+3, then ⇒ b=p+q.
2. p*q = max_value (b²/2), if p=q=0.5*b, and p*q→-oo, if p>0 and q<0 or p>0 q<0.
3. example:
given 8x²+10x+3, the student rewrites it as a) 8x²+5x+5x+3 (5*5=25-max value); b) 8x²+0.01x+9.99x+3 (9.99*0.01=0.0999→0); c) 8x²-20x+30x+3 (p*q=-600).
answer: (-oo;0.5b²)
Answer:
₹ 4000
Step-by-step explanation:
Sarah's salary =₹ 30000
- one-tenth of her salary to an orphanage= 1/10*₹ 30000= ₹ 3000
- one-third of her salary is spent on food= 1/3*₹ 30000= ₹ 10000
- one-fourth of salary on rent and electricity =1/4*₹ 30000= ₹ 7500
- one-twentieth of her salary on the telephone= 1/12*₹ 30000= ₹ 2500
- donated some amount to the Prime Minister's relief fund = x
- She was left with ₹ 3000.
x= ₹ 30000- (₹ 3000+₹ 10000+₹ 7500+₹ 2500+₹ 3000)= ₹ 4000
The answer would be ay-xb
Answer: The Total $110
Step-by-step explanation:
I hope this is what you are looking for
