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4 years ago

13

Consider the lines defined by the following two equations in slope-intercept form:

1 answer:

Kisachek [45]4 years ago

4 0

A: Yes
B: The slopes are equal

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The area of a square is found by squaring one of its sides, (A = s2). A certain square has an area of z2 + 18z + 81. Factor the

masya89 [10]

Here is your answer

Given area is

z^2 + 18z + 81

= z^2 + 2× z × 9 + 9^2

[using (a+b)^2= a^2 + 2ab + b^2], we get

= (z+9)^2

we know that area of a square is represented by side^2.

So, here

Side of square is

$z+9$

HOPE IT IS USEFUL

7 0

3 years ago

Read 2 more answers

What is the justification for each step in the solution of the equation?<br><br> 5x−42=2x−1

yanalaym [24]

Answer:

<h3>39.6</h3>

Step-by-step explanation:

collecting like terms we have:

5x-2x=-1+42

equating the terms..we have:

3x=41

divide both sides by the Co-efficient of x:

3x\3=42\3

x=39.6

7 0

3 years ago

Read 2 more answers

Not sure how to do this. Help is much appreciated. :D

Free_Kalibri [48]

Answer:

m = √n/3 -k

Step-by-step explanation:

√n = 3(k + m)

=> √n/3 = k + m

∴ m = √n/3 -k

Hope this helps!!

6 0

3 years ago

What is the resulting equation when the expression for y in the second equation is substituted into the first equation?

Anni [7]

Answer: 3x + 6 -4x = 1

Simplify to -x + 6 = 1 because 3x - 4x = -1x

5 0

4 years ago

Respuesta de (-0.5)²

Vladimir79 [104]

Answer:

0.25

Step-by-step explanation:

we have

$(-0.5)^2$

we know that

$-0.5=-\frac{1}{2}$

substitute

$(-\frac{1}{2})^2=(-\frac{1}{2})(-\frac{1}{2})$

Remember that

$(-1)(-1)=1\\(-1)(1)=(-1)$

so

$(-\frac{1}{2})(-\frac{1}{2})=\frac{1}{4}=0.25$

5 0

3 years ago