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sweet-ann [11.9K]
3 years ago
12

After modifying the font of the Subheading1 style, you notice that the font of Subheading2 has also changed. What is the most li

kely reason for this?
A. The Subheading1 style is based on the Subheading2 style.
B. The Subheading2 style is based on the Subheading1 style.
C. The styles are both based on a Subheading3 style.
D. The styles are based on the Normal default style.
Computers and Technology
2 answers:
navik [9.2K]3 years ago
8 0

<u>Answer:</u>

The correct answer option is B. The sub-heading 2 style is based on the sub-heading 1 style.

<u>Explanation:</u>

If you are modifying the font of the sub-heading 1 style in any document, you may notice that the font of the sub-heading 2 has also changes.

The reason behind this is that the style of sub heading 2 is dependent on the style of the sub-heading 1.

It is like a hierarchy that is to be followed by the style of all the next sub headings.

Elina [12.6K]3 years ago
6 0

Answer

B.Subheading 2 style is based on the Subheading 1 style


Explanations

It is possible to change the heading and subheading styles in Microsoft office.Any change which is made using the main Home tab toolbar causes the creation of an extra style which causes the formation of a major headings not consistent with each other.

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In java, c or c++ code, when a number begins with a leading 0, what do you know about that number: (example: int zzz = 012;) in
Katarina [22]
A leading 0 denotes octal notation, so the digits 8 and 9 are not used.
In normal decimal notation 12 means 1*10+2, in octal, it means 1*8+2.

The leading 0x denotes hexadecimal notation, here the digits are extended with 6 letters, a through f. 0x12 means 1*16+2.

Without any prefix, we have normal decimal notation.
5 0
4 years ago
11. What is the hexadecimal representation of each of the following binary numbers? a. 1100 1111 0101 0111
Marat540 [252]

Answer:

(a) 1100 1111 0101 0111_{2} = CF57_{16}

Explanation:

To convert from binary to hexadecimal, convert each 4 binary digits to its hexadecimal equivalent according to the following;

<em>Binary => Hex</em>

0000  => 0

0001   => 1

0010   => 2

0011    => 3

0100   => 4

0101    => 5

0110    => 6

0111     => 7

1000   => 8

1001    => 9

1010    => A

1011     => B

1100    => C

1101     => D

1110     => E

1111      => F

(a) 1100 1111 0101 0111

=> Taking the first four binary digits : 1100

According to the table, the hexadecimal equivalent is C

=> Taking the second four binary digits : 1111

According to the table, the hexadecimal equivalent is F

=> Taking the third four binary digits : 0101

According to the table, the hexadecimal equivalent is 5

=> Taking the last four binary digits : 0111

According to the table, the hexadecimal equivalent is 7

Therefore, the hexadecimal representation of

1100 1111 0101 0111 is CF57

3 0
3 years ago
In a circular linked list the last node points to the____ node.
horsena [70]

Answer: option A) First

In a circular linked list the last node points to the first node.

Explanation: As in a circular linked list, the node will point to its next node. Since the node next to last node is the first node hence last node will point to first node in a circular way. The elements points to each other in a circular path which forms a circular chain.

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4 years ago
Do all websites use the same coding to create?
Eduardwww [97]

I think not but I'm not sure

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3 years ago
Write a loop that reads positive integers from console input, printing out those values that are even, separating them with spac
zvonat [6]

Hello, since you did not specify a programming language, I wrote this algorithm in C++. Good luck!

<h2>Code:</h2>

#include <iostream>

#include <vector>

std::vector<int> v;

int main(int argc, char* argv[]) {

   while(1) {

   int temp;

   std::cout << "\nEnter a number: ";std::cin>>temp;

   

   if(temp<0) {

       std::cout << "\nEven number(s) is/are:\n---------------------\n";

       for(int i=0;i<v.size();i++) {

           if(v.at(i)%2==0) std::cout << v[i] << " ";

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       }

       std::cout << std::endl;

       break;

   }else {

       v.push_back(temp);

   }

}

   return 0;

}

4 0
2 years ago
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