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zhuklara [117]
4 years ago
10

What value(s) of x will make the expression x^2-4/x^2-9 undefined?

Mathematics
1 answer:
ziro4ka [17]4 years ago
6 0

Answer:

a

Step-by-step explanation:

a is the answer

a is the answer

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Aneli [31]
Since 3 < pi < 4, 
<span>√9 < pi √16 </span>

<span>In fact, since pi^2 = 9.86, </span>

<span>√9 < pi < √10
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6 0
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Prove the identity arcsin((x-1)/(x+1))=2arctan<img src="https://tex.z-dn.net/?f=%20%5Csqrt%7Bx%7D%20" id="TexFormula1" title=" \
kipiarov [429]
One way would be to notice that both functions have the same derivative and then find out what the "constant" is by plugging in x=0
x
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Here's another way. Look at
π2−2arctanx−−√=2(π4−arctanx−−√)=2(arctan1−arctanx−−√).
π
2
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Now remember the identity for the difference of two arctangents:
arctanu−arctanv=arctanu−v1+uv.
arctan
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u
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⁡
u
−
v
1
+
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v
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(This follows from the usual identity for the tangent of a sum.) The left side above becomes
2arctan1−x−−√1+x−−√.
2
arctan
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1
−
x
1
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x
.
The double-angle formula for the sine says sin(2u)=2sinucosu
sin
⁡
(
2
u
)
=
2
sin
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u
cos
⁡
u
. Apply that:
sin(2arctan1−x−−√1+x−−√)=2sin(arctan1−x−−√1+x−−√)cos(arctan1−x−−√1+x−−√)
sin
⁡
(
2
arctan
⁡
1
−
x
1
+
x
)
=
2
sin
⁡
(
arctan
⁡
1
−
x
1
+
x
)
cos
⁡
(
arctan
⁡
1
−
x
1
+
x
)
Now remember that sin(arctanu)=u1+u2−−−−−√
sin
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(
arctan
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u
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=
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1
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u
2
and cos(arctanu)=11+u2−−−−−√
cos
⁡
(
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u
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1
+
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Then use algebra:
2⋅(1−x√1+x√)1+(1−x√1+x√)2−−−−−−−−−−√⋅11+(1−x√1+x√)2−−−−−−−−−−√=1−x1+x.
8 0
3 years ago
Item 5 There are 20 balls in a bag. Ten of the balls are red, 4 are green, and the rest are yellow. Which ratio represents the n
OlgaM077 [116]

Answer:

3:5 <em>the colon is needed to represent the ratio</em>

Step-by-step explanation:

r = 10

g = 4

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y = 6

so ratio of total balls is 10:4:6

and ratio of y:r is

6:10

simply by dividing by 2

3:5

4 0
3 years ago
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Answer:

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