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yulyashka [42]
3 years ago
15

A jogger is going around a circular track with a radius of 100 ft. Determine the

Mathematics
1 answer:
sweet-ann [11.9K]3 years ago
3 0

Answer:

ω= 0.01 rad/s

Step-by-step explanation:

The given data is question is ,

  • r = 100ft .
  • t = 3 min = 180s.

Firstly let's find the linear speed. Which is

=> v = Circumference/time

=> v = 2πr/180s

=> v = 3.14 × 100ft ./ 90

=> v = 3.48 ft/s ≈ 1m/s

  • Now the angular speed and linear speed are related as follows ,

=> v = r\omega

=> \omega = v/r

=> \omega = 1/100

=> \omega = 0.01 rad/s

<h3><u>Hence </u><u>the</u><u> </u><u>angular</u><u> speed</u><u> </u><u>is </u><u>0</u><u>.</u><u>0</u><u>1</u><u> </u><u>rad/</u><u>s.</u></h3>
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Out of 100 emails, 60 are spam and 48 of those contain the word buy. Of the remaining 40 emails that are not spam, only 4 emails
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Answer with Step-by-step explanation:

                               Contain Buy              Do not contain Buy        Total

Spam                           48                                    12                             60

Not Spam                     4                                     36                             40

P(it contains the word buy and it is spam)=48/100

P(It is spam)=60/100

Baye's theorem states that:

P(A given B)=P(A∩B)/P(B)

P( it contains the word buy, Given that an email is spam)

=P(it contains the word buy and it is spam)/P(It is spam)

= 0.48/0.60

=0.80

Hence, Correct option is:

A.] 0.80

5 0
3 years ago
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Daniela and Jack are hiking a steady incline. They use their GPS device to determine their elevation every 15 minutes. At 15 min
kow [346]

Answer:

h=40t+9700

where the elevation, h, is in feet and time, t, is in minutes.

Step-by-step explanation:

At the time, t_1=15 min, the elevation, h_1= 10,300 feet and

at the time t_2= 30 min, the elevation, h_2=10,900 feet.

As they are hiking a steady incline, so the change in the elevation with respect to time will be constant.

So, there will be a linear relationship between the elevation and the time.

Let h be the elevation at any time instant t, so the linear relation among these quantities is

h=mt+C_0\;\cdots(i)

where m is the rate of change of elevation with respect to time and C_0 is constant.

The change in the elevation, \Delta h=h_2-h_1= 10,900-10,300=600 feet.

and the change in time, \Delta t=t_2-1_1=30-15=15 min.

So, change in the elevation in unit time,

m=\frac{\Delat h}{\Delta t}=\frac{600}{15}=40 feet/min.

Now, from equation (i)

h=40t+C_0

As the elevation, h=h_1 at time t=t_1, so

10,300=40\times15+C_0

\Rightarrow C_0=9700

Hence, the required equation is

h=40t+9700

where the elevation, h, is in feet and time, t, is in minutes.

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