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joja [24]
3 years ago
8

Fourteen elements are found in very small quantities in the cell but are required for cells to survive. what are these elements

called?
Biology
1 answer:
Alex787 [66]3 years ago
3 0

Certain elements are required in large quantities, and others are required in small amounts by the body, but both are essential for the survival of the cells. The cells which are required in large amounts are called as macronutrients, while the ones required in small quantities are called as micronutrients, or trace elements.

Hence, the answer is trace elements or micronutrients.

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State two functions of the onjective lens on a microscope​
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Answer:

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Explanation:

In microscopy, the objective lenses are the optical elements closest to the specimen. The objective lens gathers light from the specimen, which is focused to produce the real image that is seen on the ocular lens. Objective lenses are the most complex part of the microscope due to their multi-element design.

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The survival of a species depends on
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In CaF2, the oxidation number of Ca is , and that of F is . In H2SO4, the oxidation number of H is , that of S is , and that of
Bess [88]

Answer:

1. The oxidation number of Ca is 2, F is -1 in CaF₂

2. The oxidation number of H is 2, S is 6, O is -8 in H₂SO₄

3. The oxidation number of Ca is 2, S is 6, O is -8 in CaSO₄

4. The oxidation number of H is 1, F is -1 in HF

Explanation:

To get the oxidation number, we need to take the oxidation number of the whole compound 0. Then we need to know the oxidation number of the other elements and we need to take 'x' as the oxidation number of the unknown element.

Example:

In case of CaSO₄,

We can write an equation as-

CaSO₄ = 0

If we need to know the oxidation number of S

We can write the equation like this-

→2+ x+ (-2*4) = 0 (as we know the oxidation number of Ca is 2 as it has two electrons in its last shell which it gives to other elements to form bonds and the oxidation number of O is -2 as it takes 2 electrons to complete its outer shell)

→2+ x+ (-8) = 0

→2+ x- 8 = 0

→x- 6 = 0

→x = 6; which is the oxidation number of S

                       

6 0
3 years ago
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