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vivado [14]
2 years ago
10

For a moving object, the force is acting on the object varies directly with the object’s acceleration. When a force of 9 N acts

on a certain object, the acceleration of the object is 3 m/s^2. If the acceleration of the object becomes 4 m/s^2, what is the force?
Mathematics
1 answer:
svetlana [45]2 years ago
8 0

Answer:

12 Newtons

Step-by-step explanation:

We can use Newton’s Second Law to find the mass first.

F = ma

9 = 3m

mass = 3

Substitute this into the second equation.

F = ma

F = 3(4)

F = 12N

Hope this helps! :D

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*PLEASE ANSWER* What is the area of minor sector AOB?
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<h3>Answer: Approximately 13 square units (choice B)</h3>

===========================================================

Explanation:

The given reflex angle is 215 degrees. A reflex angle is anything over 180 degrees, but less than 360. Subtract 215 from 360 to get the measure of angle AOB

angle AOB = 360 - 215 = 145

angle AOB = 145 degrees

We'll use this later.

Now find the area of the full circle. Use the formula A = pi*r^2. The radius is r = sqrt(10) which can be found through the distance formula or the pythagorean theorem. You want to find the length of either OA or OB to get the radius.

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A = 10pi

This is the exact area of the full circle, but we want just a fractional portion of it. Specifically we want the pie slice that is formed by angle AOB

area of sector AOB = [ (angle AOB)/360 ] * (area of full circle)

area of sector AOB = (145/360)*10pi

area of sector AOB = 145pi/36

area of sector AOB = 145*3.14/36

area of sector AOB = 12.647 approximately

area of sector AOB = 13 square units approximately, after rounding to the nearest whole number

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