A ↔ B ↔ C ↔ D ↔ E ↔ F
8 7
???
AB + BC + CD = AD <em>segment addition postulate</em>
+ 8 + 7 = AD
+ 15 = AD
AD + 60 = 4AD
60 = 3AD
20 = AD
AB =
=
= 5
DE =
=
= 4
CD + DE + EF = CF <em>segment addition postulate</em>
7 + 4 + EF = CF
11 + EF = CF
Answer: 11 + EF
Note: You did not provide any info about EF. If you have additional information that you did not type in, calculate EF and add it to 11 to find the length of CF.
Answer:
81
Step-by-step explanation:
Sorry this question does not sense..... 81
is evaluated
maybe I don't understand the terminology
Answers + Step-by-step explanation :
a) the equation should be:
7(n + 5) = 91 since you first add 5 to n and then multiply it by 7. The answer is 91 so that is on the other side of the equal sign
b) we can solve our equation to find for n, the number jim thought of
7(n + 5) = 91
I will use the distributive property.
7n + 35 = 91
Subtract 35 on both sides
7n = 56
Now divide 7 on both sides to find n
n = 8
The number Jim was thinking of was 8! this should be correct, hope this helps!
The correct Option is (A) 35x^3 - 16x^2 + 44x - 48
Explanation: The product of the polynomials (5x^2 + 2x +8)(7x-6) is:
(5x^2)(7x-6) + 2x(7x-6) +8(7x-6)
35x^3 -30x^2 + 14x^2 - 12x + 56x - 48
35x^3 - 16x^2 + 44x - 48 (Option A)