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Step2247 [10]
2 years ago
15

Using the slope​ formula, find the slope of the line through the given points ( 9, 4 ) and ( 4, 4 )

Mathematics
2 answers:
irakobra [83]2 years ago
8 0

Answer: 0

Step-by-step explanation: it’s undefined

Sloan [31]2 years ago
6 0

Answer:

y2-y1 over x2-x1

Step-by-step explanation:

so pick one and make it 1 and pick the other and make it 2 and fill in for x and y.

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How is (5^-3) written as repeated multiplication?
stich3 [128]

Answer:

To write repeated multiplication of the same number in exponential notation, first write the number being multiplied as the base. Then count how many times that number is used in the multiplication, and write that number as the exponent.

Step-by-step explanation:

5 0
2 years ago
Step 1 5x- y= 4
valkas [14]

Answer: C, In Step 2 the expression for y should be subsituted in the other equation.

5 0
2 years ago
Solve x - 6x = 40 by factoring. What is<br> the solution?
marta [7]

Answer:

x=-8

Step-by-step explanation:

collect like terms

-5x=40

divide both sides of the equation by -5

so the answer would be x=-8

7 0
2 years ago
Please help with the question in the picture!
Stella [2.4K]

Answer:

Tan C = 3/4

Step-by-step explanation:

Given-

∠ A = 90°, sin C = 3 / 5

<u>METHOD - I</u>

<u><em>Sin² C + Cos² C = 1</em></u>

Cos² C = 1 - Sin² C

Cos² C = 1 - \frac{9}{25}

Cos² C = \frac{25 - 9}{25}

Cos² C = \frac{16}{25}

Cos C = \sqrt{\frac{16}{25} }

Cos C = \frac{4}{5}

As we know that

Tan C = \frac{Sin C}{Cos C }

<em>Tan C = \frac{\frac{3}{5} }{\frac{4}{5} }</em>

<em>Tan C = \frac{3}{4}</em>

<u>METHOD - II</u>

Given Sin C = \frac{3}{5} = \frac{Height}{Hypotenuse}

therefore,  

AB ( Height ) = 3; BC ( Hypotenuse) = 5

<em>∵ ΔABC is Right triangle.</em>

<em>∴ By Pythagorean Theorem-</em>

<em>AB² + AC² = BC²</em>

<em>AC² </em><em>= </em><em>BC² </em><em>- </em><em> AB</em><em>² </em>

<em>AC² = 5² - 3²</em>

<em>AC² = 25 - 9</em>

<em>AC² = 16</em>

<em>AC  ( Base) = 4</em>

<em>Since, </em>

<em>Tan C = \frac{Height}{Base}</em>

<em>Tan C = \frac{AB}{AC}</em>

<em>Hence Tan C = \frac{3}{4}</em>

<em />

4 0
2 years ago
Which of the following is not a factor of x^3 – 3x^2 – 4x + 12?
Slav-nsk [51]

Answer:

c. (x + 3)

Step-by-step explanation:

using factor theorem

if x - 3 is a factor then p(a) = 0

p(a)= x^3 - 3x^2 - 4x + 12

a.(x-3)

p(3) = (3)^3 - 3(3)^2 - 4(3) + 12

= 27 - 27 - 12 + 12

= 0

therefore x-3 is a factor

b.(x + 2)

p(-2) = (-2)^3 - 3(-2)^2 - 4(-2) + 12

= -8 -12 + 8 + 12

,= 0

therefore x + 2 is a factor

c.(x + 3)

p(-3) = (-3)^3 - 3(-3)^2 - 4(-3) + 12

= -27 -27 + 12 + 12

= -30

therefore x + 3 is not a factor

d.(x-2)

p(2) = (2)^3 - 3(2)^2 - 4(2) + 12

= 8 -12 - 8 + 12

= 0

therefore x - 2 is a factor

4 0
3 years ago
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