Answer: (x^2)/25 + (16y^2)/375) = 1
Step-by-step explanation:
since foci are symetrically located on x-axis about origin, the equation of the ellipse must be of the following form:
(x^2)/(a^2) + (y^2)/(b^2) = 1, where a = semi-major axis, and b = semi-minor axis,
and: e = eccentricity = sqrt(a^2 - b^2)/a = 0.25; foci located at (+/- sqrt(a^2 - b^2),0) = (+/- 1.25,0)
---> sqrt(a^2 - b^2) = 1.25 ---> 1.25/a = 0.25 ---> a = 1.25/0.25 ---> a = 5; and sqrt(a^2 - b^2) = 1.25 = 5/4
---> a^2 - b^2 = (5/4)^2 = 25/16; or 5^2 - b^2 = 25/16 ---> 25 - b^2 = 25/16;
---> b^2 = 25 - (25/16) = 25[1 - 1/16] = 25(15)/16 = 375/16
---> (x^2)/25 + (y^2)/(375/16) = 1 ---> (x^2)/25 + (16y^2)/375) = 1
Hope this help...and correct it's been awhile..Let me know
Answer:
work is shown and pictured
Step-by-step explanation:
Answer:
probability of a crash with at least one fatality if a driver drives while legally intoxicated (BAC greater than 0.09) = 0.001932
Step-by-step explanation:
P(BAC=0|Crash with fatality)=0.625
P(BAC is between .01 and .09|Crash with fatality)=0.302
P(BAC is greater than .09|Crash with fatality)=0.069
Let the event of BAC = 0 be X
Let the event of BAC between 0.01 and 0.09 be Y
Let the event of BAC greater than 0.09 be Z
Let the event of a crash with at least one fatality = C
P(X|C) = 0.625
P(Y|C) = 0.302
P(Z|C) = 0.069
P(C) = 0.028
probability of a crash with at least one fatality if a driver drives while legally intoxicated (BAC greater than 0.09) = P(C n Z)
But note that the conditional probability of probability that a driver is intoxicated (BAC greater than 0.09) given that there was a crash that involved at least a fatality is given by
P(Z|C) = P(Z n C)/P(C)
P(Z n C) = P(Z|C) × P(C) = 0.069 × 0.028 = 0.001932
Hope this Helps!!!
