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Karo-lina-s [1.5K]
3 years ago
9

An artifact originally had 16 grams of​ carbon-14 present. the decay model upper a equals 16 e superscript negative 0.000121 ta=

16e−0.000121t describes the amount of​ carbon-14 present after t years. use the model to determine how many grams of​ carbon-14 will be present in 90769076 years.
Chemistry
2 answers:
Wittaler [7]3 years ago
5 0

Answer:

After 9076 years, there are present 5,34g of ¹⁴C

Explanation:

The radioactive decay of ¹⁴C is:

¹⁴C → ¹⁴N + β

Kinetic decay model take the form of:

A = A₀ exp(-kt)

Where A is the concentration of ¹⁴C after t time

Based on the given data:

A = 16 * exp(-0.000121*9076) = 16(0.3335) = 5,34g

<em>After 9076 years, there are present 5,34g of ¹⁴C</em>

<em />

I hope it helps!

xeze [42]3 years ago
3 0

<u>Given:</u>

Initial amount of carbon, A₀ = 16 g

Decay model = 16exp(-0.000121t)

t = 90769076 years

<u>To determine:</u>

the amount of C-14 after 90769076 years

<u>Explanation:</u>

The radioactive decay model can be expressed as:

A = A₀exp(-kt)

where A = concentration of the radioactive species after time t

A₀ = initial concentration

k = decay constant

Based on the given data :

A = 16 * exp(-0.000121*90769076) = 16(0) = 0

Ans: Based on the decay model there will be no C-14 left after 90769076 years

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Answer:

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For the given reaction:

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In the reactants, there are 3 C, and in the products only one, so we multiply CO₂ by 3:

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