Question

An artifact originally had 16 grams of​ carbon-14 present. the decay model upper a equals 16 e superscript negative 0.000121 ta=16e−0.000121t describes the amount of​ carbon-14 present after t years. use the model to determine how many grams of​ carbon-14 will be present in 90769076 years.

Answer 1

Answer:

After 9076 years, there are present 5,34g of ¹⁴C

Explanation:

The radioactive decay of ¹⁴C is:

¹⁴C → ¹⁴N + β

Kinetic decay model take the form of:

A = A₀ exp(-kt)

Where A is the concentration of ¹⁴C after t time

Based on the given data:

A = 16 * exp(-0.000121*9076) = 16(0.3335) = 5,34g

After 9076 years, there are present 5,34g of ¹⁴C

I hope it helps!

Answer 2

Given:

Initial amount of carbon, A₀ = 16 g

Decay model = 16exp(-0.000121t)

t = 90769076 years

To determine:

the amount of C-14 after 90769076 years

Explanation:

The radioactive decay model can be expressed as:

A = A₀exp(-kt)

where A = concentration of the radioactive species after time t

A₀ = initial concentration

k = decay constant

Based on the given data :

A = 16 * exp(-0.000121*90769076) = 16(0) = 0

Ans: Based on the decay model there will be no C-14 left after 90769076 years