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3 years ago

A reaction releases 489.34 J of heat how many calories of heat is that equal to 1 cal equals 4.186 J

Chemistry

1 answer:

Verdich [7]3 years ago

6 0

The answer is equal to 115.47 calories. Just devide the amount of heat release by 4.186 J because it is equal to 1 cal

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I need help with this, please :00000

mojhsa [17]

theoretical yield of the reaction is 121.38 g of NH₃ (ammonia)

limiting reactant is N₂ (nitrogen)

excess reactant is H₂ (hydrogen)

Explanation:

We have the following chemical reaction:

N₂ + 3 H₂ → 2 NH₃

Now we calculate the number of moles of each reactant:

number of moles = mass / molar weight

number of moles of N₂ = 100 / 28 = 3.57 moles

number of moles of H₂ = 100 / 2 = 50 moles

From the chemical reaction we see that 3 moles of H₂ are reacting with 1 moles of N₂, so 50 moles of H₂ are reacting with 16.66 moles of N₂ but we only have 3.57 moles of N₂ available, so the limiting reactant will be N₂ and the excess reactant will be H₂.

Knowing the chemical reaction and the limiting reactant we devise the following reasoning:

if 1 mole of N₂ produce 2 moles of NH₃

then 3.57 moles of N₂ produce X moles of NH₃

X = (3.57 × 2) / 1 = 7.14 moles of NH₃

mass = number of moles × molar weight

mass of NH₃ = 7.14 × 17 = 121.38 g

theoretical yield of the reaction is 121.38 g of NH₃

Learn more about:

limiting reactant

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4 0

4 years ago

A sample of liquid mercury is heated from 20°C to 40°C. Which measurement of the sample will increase during this process? volum

Paladinen [302]

its volume this is the answer because the mercury will turn into gas. gas has more volume because it takes up more space as it spreads.

3 0

3 years ago

You are in a laboratory creating a new chocolate bar. You want to create the sweetest chocolate bar by maximizing the sugar conc

svetoff [14.1K]

Water helps dissolve sugar

3 0

3 years ago

Read 2 more answers

The partial pressure of CO2 inside a bottle of soft drink is 4.0 atm at 25°C. The solubility of CO2 is 0.12 mol/L. When the bott

navik [9.2K]

We can solve this problem by using Henry's law.
Henry's law states that the amount of dissolved gas is proportional to its partial pressure.
$C=kP$
C is the solubility of a gas.
k is Henry's law constant.
P is the partial pressure of the gas.
We can calculate the constant from the first piece of information and then use Henry's law to calculate solubility in open drink.
0.12=4k
k=0.03
Now we can calculate the solubility in open drink.
$C_o=kP_o
$
$C_o=0.03 \cdot 3\cdot 10^{-4}=0.09\cdot 10^{-4} \frac{mol}{L}$
Now we need to convert it to g/L. One mol of CO2 is 44.01g.
The final answer is:
$C_o=0.09\cdot 10^{-4}\cdot 44,01=3.4\cdot 10^{-4} \frac{g}{L}$

4 0

3 years ago

What mass of each solute is present in 294 g of a solution that contains 4.86% by mass NaCl and 7.54% by mass Na2CO3

Angelina_Jolie [31]

In order to compute the mass of each solute in the sample, we simply multiply the percentage mass of each solute with the total mass of the solution. This is ad such:
Mass (NaCl) = 0.0486 x 294
Mass (NaCl) = 14.29 grams

Mass(Na₂CO₃) = 0.0754 x 294
Mass(Na₂CO₃) = 22.17 grams

7 0

3 years ago