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3 years ago

A reaction releases 489.34 J of heat how many calories of heat is that equal to 1 cal equals 4.186 J

Chemistry

1 answer:

Verdich [7]3 years ago

6 0

The answer is equal to 115.47 calories. Just devide the amount of heat release by 4.186 J because it is equal to 1 cal

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The given balanced equilibrium reaction is,

$CO(g)+Cl_2(g)\rightleftharpoons COCl_2(g)$

Initial conc. 0.860M 0.860M 0

At eqm. conc. (0.860-x) M (0.860-x) M (x) M

The expression for equilibrium constant for this reaction will be,

$K_c=\frac{[COCl_2]}{[CO][Cl_2]}$

Now put all the given values in this expression, we get :

$4.95=\frac{x}{(0.860-x)^2}$

By solving the term 'x', we get :

x = 0.532 M

Thus, the concentrations of $CO,Cl_2\text{ and }COCl_2$ at equilibrium are :

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