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alisha [4.7K]
2 years ago
9

Sufficient strong acid is added to a solution containing Na2HPO4 to neutralize one-half of it. what will be the pH of this solut

ion? Explain please
Chemistry
1 answer:
34kurt2 years ago
5 0
The neutralization of the base with an acid will result to the formation of salt and water. In this case, a mole of strong acid will have one halide that will react with the Na atom. Since there are two Na atoms in each of the molecule of Na2HPO4, this will need 2 halide atoms. 
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3 years ago
An unknown or changeable quantity is called a(n)...
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3 years ago
If the temperature of a liquid-vapor system at equilibrium increases, the new equilibrium condition will
nikdorinn [45]
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2 years ago
When adjusted for any changes in ΔHΔH and ΔSΔS with temperature, the standard free energy change ΔG∘TΔGT∘Delta G_{T}^{\circ} at
STALIN [3.7K]

The equilibrium constant is 0.0022.

Explanation:

The values given in the problem is

ΔG° = 1.22 ×10⁵ J/mol

T = 2400 K.

R = 8.314 J mol⁻¹ K⁻¹

The Gibbs free energy should be minimum for a spontaneous reaction and equilibrium state of any reaction is spontaneous reaction. So on simplification, the thermodynamic properties of the equilibrium constant can be obtained as related to Gibbs free energy change at constant temperature.

The relation between Gibbs free energy change with equilibrium constant is ΔG° = -RT ln K

So, here K is the equilibrium constant. Now, substitute all the given values in the corresponding parameters of the above equation.

We get,

1.22 * 10^{5} = - 8.314* 2400 * ln K

\\ 1.22 * 10^{5} = -19953.6 * ln K

ln K = \frac{-1.22*10^{5} }{19953.6} =-6.114\\\\k =e^{-6.114}=0.0022

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3 years ago
Question 11 of 25
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2 years ago
Read 2 more answers
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