<u>Answer:</u>
A curve is given by y=(x-a)√(x-b) for x≥b. The gradient of the curve at A is 1.
<u>Solution:</u>
We need to show that the gradient of the curve at A is 1
Here given that ,
--- equation 1
Also, according to question at point A (b+1,0)
So curve at point A will, put the value of x and y
0=b+1-c --- equation 2
According to multiple rule of Differentiation,
so, we get
By putting value of point A and putting value of eq 2 we get
Hence proved that the gradient of the curve at A is 1.
Answer:
3√41
Step-by-step explanation:
The diagonal can be gotten using the pythagoras theorem
d² = l²+w²
d² = 12²+15²
d² = 144 + 225
d² = 369
d = √9*41
d = 3√41
Hence the diagonal is 3√41
We can see both terms have a (x-2) in them.
We can also see that 8 and 2 are both even so there is a 2 in common.
This means that the gcd or hcf or whatever you call it is 2(x-2)
**Just mentioning most of the time we call it the GCD(greatest common divisor) or the GCF(greatest common factor) and almost never uses hcf :)
The measure of angle 6 is 84 :)
