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quester [9]
3 years ago
5

What is the denominator of zero

Mathematics
1 answer:
Snowcat [4.5K]3 years ago
3 0

Answer:Any number

Step-by-step explanation:

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5^4÷ 5^6=5^-2

1 over 25

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X 6.4.5-T
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Same strategy as before: transform <em>X</em> ∼ Normal(76.0, 12.5) to <em>Z</em> ∼ Normal(0, 1) via

<em>Z</em> = (<em>X</em> - <em>µ</em>) / <em>σ</em>   ↔ <em>X</em> = <em>µ</em> + <em>σ</em> <em>Z</em>

where <em>µ</em> is the mean and <em>σ</em> is the standard deviation of <em>X</em>.

P(<em>X</em> < 79) = P((<em>X</em> - 76.0) / 12.5 < (79 - 76.0) / 12.5)

… = P(<em>Z</em> < 0.24)

… ≈ 0.5948

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Find the distance between the two points in simplest radical form. (−3,6) and (−8,−6)
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Answer: The distance between the two points is 13.

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2 years ago
. Mrs. Rojas deposited $8000 into an account paying 4% interest annually. After 8 months Mrs. Rojas withdrew the $6000 plus inte
Mashcka [7]

well, keeping in mind that a year has 12 months, that means that 8 months is 8/12 of a year, when Mrs Rojas pull her money out.

~~~~~~ \textit{Simple Interest Earned Amount} \\\\ A=P(1+rt)\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill & \$6000\\ r=rate\to 4\%\to \frac{4}{100}\dotfill &0.04\\ t=years\to \frac{8}{12}\dotfill &\frac{2}{3} \end{cases} \\\\\\ A=6000[1+(0.04)(\frac{2}{3})]\implies A=6000\left( \frac{77}{75} \right)\implies A=6160

well, she put in 6000 bucks, got back 160 extra, that's the interest earned in the 8 months.

what if she had left her money for 1 whole year, then

~~~~~~ \textit{Simple Interest Earned Amount} \\\\ A=P(1+rt)\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill & \$6000\\ r=rate\to 4\%\to \frac{4}{100}\dotfill &0.04\\ t=years\dotfill &1 \end{cases} \\\\\\ A=6000[1+(0.04)(1)]\implies A=6240

so had she left it in for a year, she'd have gotten 6240, namely 240 in interest, well, what fraction of a year's interest was earned? or worded differently, what fraction is 160(8 months) of 240(1 year)?

\cfrac{\stackrel{\textit{for 8 months}}{160}}{\underset{\textit{for 12 months}}{240}}\implies \cfrac{2}{3}

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A orchard has 48 apple trees,30 peach trees, and 42 pear trees. In simplistic form, what fraction of the trees are peach trees?
choli [55]
48+30+42= 120 
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