How does depreciation affect the cost of owning a car over a period of 5 years

Mathematics

1 answer:

lutik1710 [3]4 years ago

8 0

Due to depreciation, the value of your car goes from 100% when you buy it to nearly 40% after 5 years.

Step-by-step explanation:

Depreciation means the reduction in the value of something you have with time. If you buy a car for $40,000 in 2020 and want to sell it in 2025, you will have to sell it for something near $16,000. This reduction in price is because of you owning the car and using it for that period.

After you buying a car and owning it for a year, your car's value depreciates about 20% which means your car is now worth 80% (100%-20%) of what it cost when you brought it. After owning the car for a year, the value depreciates approximately 10% every year. So for another 4 years, your value decreases another 40% (4 years x 10% per year).

To summarize, the first year the car value depreciates by 20% followed by 4 years of 10% each which is 40%. So in total after 5 years, your car loses nearly 60% of its value due to depreciation. A car brought in 2020 for $40,000 will depreciate 60% and will be valued at nearly $16,000 during 2025.

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Answer:

From Commercial spray X: 4 liters from Chemical A, 8 liters from Chemical B and 8 liters from Chemical C.
From Commercial spray Y: 18 liters of Chemical C
From Commercial spray Z: 8 liters of Chemical A and 8 liters of Chemical B.

Step-by-step explanation:

Since we need a lot of chemical C, we are going to leave Commercial spray Y for last in case we lack in case we need more Chemical C, which is supplied by spray Y.

We need to cover the demand of both chemical A and B. For each liter of Chemical A we get 2 liters of Chemical B by using Commercial spray X. And for each liter of Chemical A we get 2 liters of Chemical B by using spray Z.

We will call X the number of units of Commercial spray X used, where each unit contains 1 liter of Chemical A, 2 liters of Chemical B and 2 iters of Chemical C. Y is the number of units of Commercial spray Y used, containing each of them 1 liter of Chemical C, and Z the number of units of commercial spray Z used, on units containing both 1 liter of Chemical A and Chemical B.

We can represent the amount of liters we have for each chemical on a vector of the form (a,b,c) where a reresents the amount of Chemical A, b the amount of chemical B, and c the amount of chemical C. We want (a,b,c) to be equal to (12,16,26), in other words, we want a to be 12, b to be 16 and c to b 26. Furthermore we can obtain (a,b,c) by using this equation

(a,b,c) = X * (1,2,2) + Y * (0,0,1) + Z * (1,1,0) = (1*X+0*Y+1*Z,2*X+0*Y+1*Z,2*X+1*Y+0*Z) = (X+Z,2*X+Z,2*X+Y)

Thus, we have