Since the problem said he uses 160 feet of fence, you know that is the perimeter
P = 2l + 2w
You know that one of the dimensions is 50, so you can plug that into the equation
160 = 2 x 50 + 2w
160 = 100 + 2w
2w = 60
w = 30
The area is equal to l x w
50 x 30 = 1500 square feet
Problem 3: Let x = price of bag of pretzels Let y = price of box of granola bars
We have Lesley's purchase: 4x+2y=13.50
And Landon's: 1x+5y=17.55
We can use the elimination method. Let's negate Landon's purchase by multiplying by -1. -1x-5y=-17.55
We add this four times to Lesley's purchase to eliminate the x variable.
2y-20y=13.50-70.2
-18y=-56.7
y = $3.15 = Price of box of granola bars
Plug back into Landon's purchase to solve for pretzels.
x+5*3.15=17.55
x+15.75=17.55
x = $1.80 = price of bag of pretzels
Problem 4.
Let w = number of wood bats sold
Let m = number of metal bats sold
From sales information we have: w + m = 23
24w+30m=606
Substitution works well here. Solve for w in the first equation, w = 23 - m, and plug this into the second.
24*(23-m)+30m=606
552-24m+30m=606
6m=54
m=9 = number of metal bats sold
Therefore since w = 23-m, w = 23-9 = 14. 14 wooden bats were sold.
2x - 4 < 3x
Just follow the question.
Answer:
y-8=5/6(x-12)
Step-by-step explanation:
y-y1=m(x-x1)
y-8=5/6(x-12)
Answer:
-![\sqrt{5}](https://tex.z-dn.net/?f=%5Csqrt%7B5%7D)
Step-by-step explanation:
A root with square root or under root is only obtained when we take the square root of both sides. Remember that when we take a square root, there are two possible answers:
- One answer with positive square root
- One answer with negative square root
For example, for the equation:
![x^{2}=3](https://tex.z-dn.net/?f=x%5E%7B2%7D%3D3)
If we take the square root of both sides, the answers will be:
![x=\sqrt{3} \text{ or } x= -\sqrt{3}](https://tex.z-dn.net/?f=x%3D%5Csqrt%7B3%7D%20%5Ctext%7B%20or%20%7D%20x%3D%20-%5Csqrt%7B3%7D)
Only getting one solution with square root is not possible. Solutions with square root always occur in pairs.
For given case, the roots are 6 and
. Therefore, the 3rd root of the polynomial function f(x) had to be -![\sqrt{5}](https://tex.z-dn.net/?f=%5Csqrt%7B5%7D)
It seems you made error while writing option B, it should be - square root of 5.