Answer:
the substitution method is one way to solve linear equation. the substitution method is when substitute the one y value with the other:
example :
x+y=10
y=10-x ( value of y)
2x+y=12 ( substitute the value of y in the equation )
2x+(10-x)=12
2x+10-x=12 ( now solve for x)
x=12-10
x=2 ( substitute the value of x in the equation x+y=10)
x+y=10
2+y=10
y=10-2
y=8
( i hope it helps)
For digits 0 to 9
<span>0,1,3,8 have lines of symmtery
</span>~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
I hope that helped =)
Answer:

General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
- Multiplication Property of Equality
- Division Property of Equality
- Addition Property of Equality
- Subtraction Property of Equality<u>
</u>
<u>Algebra I</u>
- Terms/Coefficients
- Functions
- Function Notation
- Graphing
- Solving systems of equations
<u>Calculus</u>
Area - Integrals
Integration Rule [Reverse Power Rule]: 
Integration Rule [Fundamental Theorem of Calculus 1]: 
Integration Property [Addition/Subtraction]: ![\displaystyle \int {[f(x) \pm g(x)]} \, dx = \int {f(x)} \, dx \pm \int {g(x)} \, dx](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cint%20%7B%5Bf%28x%29%20%5Cpm%20g%28x%29%5D%7D%20%5C%2C%20dx%20%3D%20%5Cint%20%7Bf%28x%29%7D%20%5C%2C%20dx%20%5Cpm%20%5Cint%20%7Bg%28x%29%7D%20%5C%2C%20dx)
Area of a Region Formula: ![\displaystyle A = \int\limits^b_a {[f(x) - g(x)]} \, dx](https://tex.z-dn.net/?f=%5Cdisplaystyle%20A%20%3D%20%5Cint%5Climits%5Eb_a%20%7B%5Bf%28x%29%20-%20g%28x%29%5D%7D%20%5C%2C%20dx)
Step-by-step explanation:
*Note:
<em>Remember that for the Area of a Region, it is top function minus bottom function.</em>
<u />
<u>Step 1: Define</u>
f(x) = x²
g(x) = x⁶
Bounded (Partitioned) by x-axis
<u>Step 2: Identify Bounds of Integration</u>
<em>Find where the functions intersect (x-values) to determine the bounds of integration.</em>
Simply graph the functions to see where the functions intersect (See Graph Attachment).
Interval: [-1, 1]
Lower bound: -1
Upper Bound: 1
<u>Step 3: Find Area of Region</u>
<em>Integration</em>
- Substitute in variables [Area of a Region Formula]:
![\displaystyle A = \int\limits^1_{-1} {[x^2 - x^6]} \, dx](https://tex.z-dn.net/?f=%5Cdisplaystyle%20A%20%3D%20%5Cint%5Climits%5E1_%7B-1%7D%20%7B%5Bx%5E2%20-%20x%5E6%5D%7D%20%5C%2C%20dx)
- [Area] Rewrite [Integration Property - Subtraction]:

- [Area] Integrate [Integration Rule - Reverse Power Rule]:

- [Area] Evaluate [Integration Rule - FTC 1]:

- [Area] Subtract:

Topic: AP Calculus AB/BC (Calculus I/II)
Unit: Area Under the Curve - Area of a Region (Integration)
Book: College Calculus 10e
Answer:
<h3>A4root13 или С 4root5</h3>
Step-by-step explanation:
Answer:
11 am
Step-by-step explanation:
Bus A and Bus B leave the bus depot at 9 am.
Bus A takes 30 minutes to complete its route once
Bus B takes 40 minutes to complete its route once.
We solve this finding the Lowest Common Multiple of the minutes each bus uses to complete it's route
30 = 3 × 10
40 = 4 × 10
= 3 × 4 × 10
= 120 minutes
120 minutes after 9 am is
60 minutes = 1 hour
60 minutes = 1 hour
= 2 hours.
9am + 2 hours
= 11 am.
Therefore, they be back at the bus depot together at 11 am