What is the sum of 1015 and 119?

1 answer:

6 0

You'd likely find this problem easier if you'd write these two numbers on separate lines, one above the other:

1015
+119
-------
1134

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The following statements are all incorrect. Explain the statements and the errors fully using the probability rules discussed in

bija089 [108]

The reasons for each incorrect statement are as follows;

The error in the statement is that, there might be other luckier numbers compared to number 7 and hence, the statement does not hold true for all numbers.
The statement is incorrect because, there are 36 different possibilities and there are 5 possibilities of getting an 8.
The statement is incorrect because, 93% does not necessarily represent a 93% chance of complete recovery as this is subject to other variables.
The probability that they win is not 1/3 as it is subject to what the results have been over the years and not just the possible results.
Since, the coin is unbiased, it follows that upon flipping the coin for the fifth time, it is not likely to have tails the next time it is flipped.
The statement is incorrect because some students study during the week and weekends, hence, the conclusion is not correct.

<h3>What is Probability?</h3>

The term probability put simply is the ratio of the desired outcome to the possible outcomes. It therefore follows that probability as the name implies is used to predict the chance of an occurrence.

Read more on probability;

brainly.com/question/24756209

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3 0

2 years ago

Read 2 more answers

Help please! Please put the answers numbered!

Nesterboy [21]

1: ‘8’/3x = 1+ 5/3x
2: ‘8’/3x-5/3x= 1+ 5/3x-‘5/3x’
3: ‘3’/3x=1
4: 1

4 0

3 years ago

Franklin rolls a pair of six-sided fair dice with sides numbered 1 through 6.

Zarrin [17]

Answer:

The answer is 7/36.

Step-by-step explanation:

First, you find out how many possible outcomes there are from rolling a pair of dice. On one cube, you can roll a 1,2,3,4,5, or 6; so there are 6 outcomes. Since there are two cubes, you multiply 6 by itself to get a total of 36 possible outcomes. Next, you find the probability of the sum of the numbers rolled being an even number; the possibilities are 2,4,6,8,10, or 12, which is 6/36. The probability of rolling a multiple of 5; the one possibility is just 5, since we already accounted for rolling a 10 as an even number. So that is 1/36. The word <u>or</u> says that we add the two probabilities, so the final answer is 6/36+1/36=7/36.

6 0

3 years ago

Please answer this question only if you know the answer! :(

Paul [167]

A is not a line of symmetry

3 0

3 years ago

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How many zeroes do we write when we write all the integers 1 to 243 in base 3?

Monica [59]

Answer:

289 numbers

Step-by-step explanation:

Above you will find the list of integers from 1 to 243 in base 3:

(1, 2, 10, 11, 12, 20, 21, 22, 100, 101, 102, 110, 111, 112, 120, 121, 122, 200, 201, 202, 210, 211, 212, 220, 221, 222, 1000, 1001, 1002, 1010, 1011, 1012, 1020, 1021, 1022, 1100, 1101, 1102, 1110, 1111, 1112, 1120, 1121, 1122, 1200, 1201, 1202, 1210, 1211, 1212, 1220, 1221, 1222, 2000, 2001, 2002, 2010, 2011, 2012, 2020, 2021, 2022, 2100, 2101, 2102, 2110, 2111, 2112, 2120, 2121, 2122, 2200, 2201, 2202, 2210, 2211, 2212, 2220, 2221, 2222, 10000, 10001, 10002, 10010, 10011, 10012, 10020, 10021, 10022, 10100, 10101, 10102, 10110, 10111, 10112, 10120, 10121, 10122, 10200, 10201, 10202, 10210, 10211, 10212, 10220, 10221, 10222, 11000, 11001, 11002, 11010, 11011, 11012, 11020, 11021, 11022, 11100, 11101, 11102, 11110, 11111, 11112, 11120, 11121, 11122, 11200, 11201, 11202, 11210, 11211, 11212, 11220, 11221, 11222, 12000, 12001, 12002, 12010, 12011, 12012, 12020, 12021, 12022, 12100, 12101, 12102, 12110, 12111, 12112, 12120, 12121, 12122, 12200, 12201, 12202, 12210, 12211, 12212, 12220, 12221, 12222, 20000, 20001, 20002, 20010, 20011, 20012, 20020, 20021, 20022, 20100, 20101, 20102, 20110, 20111, 20112, 20120, 20121, 20122, 20200, 20201, 20202, 20210, 20211, 20212, 20220, 20221, 20222, 21000, 21001, 21002, 21010, 21011, 21012, 21020, 21021, 21022, 21100, 21101, 21102, 21110, 21111, 21112, 21120, 21121, 21122, 21200, 21201, 21202, 21210, 21211, 21212, 21220, 21221, 21222, 22000, 22001, 22002, 22010, 22011, 22012, 22020, 22021, 22022, 22100, 22101, 22102, 22110, 22111, 22112, 22120, 22121, 22122, 22200, 22201, 22202, 22210, 22211, 22212, 22220, 22221, 22222, 100000)

If you count them, you will find that there are 289 numbers in total!

8 0

3 years ago