Answer:
Let the vectors be
a = [0, 1, 2] and
b = [1, -2, 3]
( 1 ) The cross product of a and b (a x b) is the vector that is perpendicular (orthogonal) to a and b.
Let the cross product be another vector c.
To find the cross product (c) of a and b, we have
![\left[\begin{array}{ccc}i&j&k\\0&1&2\\1&-2&3\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Di%26j%26k%5C%5C0%261%262%5C%5C1%26-2%263%5Cend%7Barray%7D%5Cright%5D)
c = i(3 + 4) - j(0 - 2) + k(0 - 1)
c = 7i + 2j - k
c = [7, 2, -1]
( 2 ) Convert the orthogonal vector (c) to a unit vector using the formula:
c / | c |
Where | c | = √ (7)² + (2)² + (-1)² = 3√6
Therefore, the unit vector is
or
[
,
,
]
The other unit vector which is also orthogonal to a and b is calculated by multiplying the first unit vector by -1. The result is as follows:
[
,
,
]
In conclusion, the two unit vectors are;
[
,
,
]
and
[
,
,
]
<em>Hope this helps!</em>
-3 11 -1 20
4 -12 -4 -20
-3 -1 -5 0
Bring down the -3,
Multiply -3 * 4
Add 11 and -12
Multiply -1 * 4
Add -1 and -4
Multiply -5 * 4
Add 20 and -20
Answer: The power is reduced by one from the
Dividend. -3x^2 – x - 5
I tried to upload a file also but I don't know if it will show up.
Answer:
I think 80
Step-by-step explanation:
100/15=6.66666667
12x6.67=80.4
3×(60+7)
(3×30) + (3×7)
90 + 21 = 111