PLZZZ HURRYYY!!Which graph best represents the solution to the system of equations shown below? y = -4x + 19 y = 2x + 1 A coordi
nate grid is shown from negative 10 to positive 10 on the x axis and also on the y axis. Two lines are shown intersecting on ordered pair 7, 3. A coordinate grid is shown from negative 10 to positive 10 on the x axis and also on the y axis. Two lines are shown intersecting on ordered pair 3, 7. A coordinate grid is shown from negative 10 to positive 10 on the x axis and also on the y axis. Two lines are shown intersecting on ordered pair negative 3, negative 7. A coordinate grid is shown from negative 10 to positive 10 on the x axis and also on the y axis. Two lines are shown intersecting on ordered pair negative 7, negative 3.
1 answer:
Answer:
Two lines are shown intersecting on ordered pair 3, 7.
Step-by-step explanation:
The first of the two lines has a slope of -4 and a y-intercept of 19 (off the top of the graph). It will decrease 4 units for each 1 unit to the right.
The second of the two lines has a slope of +2 and a y-intercept of +1. It will increase 2 units for each 1 unit to the right.
These two lines must intersect in the first quadrant at a point with an x-value less than 5, eliminating the first and last two choices, leaving only the second choice you have listed here.
You would have to examine the graphs to see which has the lines with proper slope and intercept.
My graphing calculator's solution is attached.
You might be interested in
Let
where we assume |r| < 1. Multiplying on both sides by r gives
and subtracting this from gives
As n → ∞, the exponential term will converge to 0, and the partial sums will converge to
Now, we're given
We must have |r| < 1 since both sums converge, so
Solving for r by substitution, we have
Recalling the difference of squares identity, we have
We've already confirmed r ≠ 1, so we can simplify this to
It follows that
and so the sum we want is
which doesn't appear to be either of the given answer choices. Are you sure there isn't a typo somewhere?