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krek1111 [17]
3 years ago
10

Evaluate 4 times a number Q + 25 when Q equals 2​

Mathematics
1 answer:
madam [21]3 years ago
8 0

Answer:

4*(Q+25)    Q=2

Step-by-step explanation:

4*(2+25)  = 4*27  =  108

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3. In AABC, a = 35, c = 25, and m can be drawn given these measurements?
Flauer [41]

Only one triangle possible with angle 38.2° at C.

According to the given statement

we have to seek out that the measurement of m with the help of the a and c.

Then for this purpose, we all know that the

The ambiguous case occurs when one uses the law of sines to see missing measures of a triangle when given two sides and an angle opposite one in every of those angles (SSA).

According to the this law

The equation become

35/sin(60) = 25/sinC

sinC = 0.6185895741

C = 38.2, 141.8

Since 141.8+60 = 201.8 > 180

It will not form a triangle.

So, only 1 triangle possible with angle 38.2° at C

Learn more about ambiguous case here

brainly.com/question/4372174

#SPJ1

Disclaimer: This question was incomplete. Please find the full content below.

Question:

Law of Sines and the Ambiguous Case.

In ∆ ABC, a =35, c = 25, and m < A = 60*

How many distinct triangles can be drawn given these measurements?

6 0
1 year ago
A repeating decimal + A fraction
AysviL [449]

Answer:

3.33333333333+1/3=3.6666666666666666

7 0
3 years ago
Read 2 more answers
PLEASE HELP ME, and explain it please please please &lt;3
ser-zykov [4K]
The answer would be f(x)= x+47
7 0
3 years ago
<img src="https://tex.z-dn.net/?f=%285y%20%2B%209%29%286y%20-%201%29" id="TexFormula1" title="(5y + 9)(6y - 1)" alt="(5y + 9)(6y
mestny [16]
Hey there :)

( 5y + 9 )( 6y - 1 )

We need to use FOIL to expand, that is
First Terms
Outer Terms
Inner Terms
Last Terms

     First          Outer         Inner      Last
( 5y )( 6y ) + ( 5y )( - 1 ) + 9 ( 6y ) + 9 ( - 1 )
    30y²     -        5y      +    54y   -       9

Combine, if any, the like-terms
30y² + 49y - 9
7 0
3 years ago
Read 2 more answers
Help with this proof
mixer [17]
Essentially, what we need to do here is prove that BE=EC, BE=CB, and.or CE=BC therefore making it isosceles. With ∠AEC=∠DEB, we know AE=DE, so EC=EB (the points go in order). Therefore, as EC=EB, BEC is isosceles (it has at least 2 equal sides).

Feel free to ask further questions! 
7 0
3 years ago
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