I haven't learned antiderivitives yet but I can try to logic it
<span>First find f′ and then find f. f′′(x)=3x^3+6x^2−x+2, f′(1)=9, f(1)=−7.
we reverse chain rule
3x^3, we know that it was a 4th degree thing, and the coefient is 3, so
4*what=3?, answer is 3/4
3/4x^4
6x^2
we know it was x^3, and the coefient is now 6 so
3*what=6? what=2
2x^3
-1x, the power was 2 and coefient is now -1, so
2 times what=-1?, -1/2
-1/2x^2
2, that is from 2x
so
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<span>3/4x^4+2x^3-1/2x^2+2x=f'(x)
test x=1
(3/4)(1)+2(1)-(1/2)(1)+2(1)=
3/4+2-2/4+2=
4 and 1/4 we need to get it to 9
4 and 1/4 +what=9
answer is 4 and 3/4
so we add that to the end since it will become 0 from derivitive
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<span>f'(x)=3/4x^4+2x^3-1/2x^2+2x+4 and 3/4
now reverse drivitive again
3/4x^4
exponent is 5 and coefient is 3/4
5 times what=3/4? answer is 3/20
3/20x^5
2x^3
exponent should be 4 and coefient is 2
4 times what=2? answer is 1/2
1/2x^4
-1/2x^2
exponent should be 3 and coefient is -1/2
3 times what=-1/2? answer is -1/6
-1/6x^3
2x
exponent should be 2 and coefient is 2
2 times what=2? answer is 1
1x^2
4 and 3/4 turns to (4 and 3/4)x
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<span>f(x)=3/20x^5+1/2x^4-1/6x^3+x^2+(4 and 3/4)x
try evaluating it for x=1
f(1)=(3/20)+(10/20)-(10/50)+1+(19/4)
f(1)=6 and 7/30
what do we add to get -7
-13 and 7/30
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<span><span>f(x)=3/20x^5+1/2x^4-1/6x^3+x^2+(4 and 3/4)x-13 and 7/30
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</span>ANSWER
<span>f'(x)=3/4x^4+2x^3-1/2x^2+2x+19/4
</span><span>f(x)=3/20x^5+1/2x^4-1/6x^3+x^2+19/4x-187/30</span>
7/y....the coefficient of y is 1
any time u have a variable by itself, whether it is x or y or any letter, the coefficient is gonna be 1
Answer:
The ratios are not equivalent
Step-by-step explanation:
First, in order to find the ratios, we have to change the month to the amount of days.
There are 30 days in April, so we will use this for the ratio.
The ratio for the 3 day weekend is 5:3
The ratio for the month of April is 60:30, which can be simplified to 2:1
So, the ratios are not equivalent, because 5:3 is not equal to 2:1
Answer:5
Step-by-step explanation:
Since Michelle (he ? ) has 11/12 quarts of paint, and need 1/6 per quart to paint, we do 11/12 / 1/6 = 11/2, or 5.5. We cannot paint .5 of a block, so Michelle can only paint 5 quarts.
The angle between two vectors is:
CosФ = u - v / Magnitude(u) x magnitude(v)
Magnitude of u = SQRT(7^2 + -2^2) = SQRT(49 +4) = SQRT(53)
Magnitude of v = SQRT(-1^2 +2^2) = SQRT(1 +4) = SQRT(5)
u x v = (7 x -1) + (-2 x 2) = -7 + -4 = -11
cosФ = -11 / sqrt(53) x sqrt(5)
cosФ = -11sqrt265) / 265
Ф =cos^-1(-11sqrt265) / 265)
Ф=132.51 degrees.
