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Degger [83]
4 years ago
5

Need help solving quadratic equations

Mathematics
1 answer:
Semenov [28]4 years ago
8 0
--------------------------------------------------------------------
Question
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3x = 0.5x²

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Take out common factor , i.e. x
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3x = 0.5x²
3x - 0.5x² = 0
x(3 - 0.5x) = 0 

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Use the Zero Product Property to solve for x
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x(3 - 0.5x) = 0
x = 0 or 3 - 0.5x = 0
x = 0 or 0.5x = 3
x = 0 or x = 3 ÷ 0.5
x = 0 or x = 6

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Answer: x = 0 or 6 (Answer D)
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Question
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0 = 5x² - 2x + 6

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Use Quadratic Formula
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x =  \frac{-b\pm  \sqrt{b^2-4ac} }{2a}

a = 5, \ b = -2, \ c = 6

x =  \frac{-(-2)\pm  \sqrt{(-2)^2-4(5)(6)} }{2(5)}

x =  \frac{2\pm  \sqrt{-116} }{10}

x = \frac{2\pm \sqrt{-4} \sqrt{29}  }{10}

x = \frac{2\pm  2i\sqrt{29} }{10}

x = \frac{1\pm i\sqrt{29} }{5}

--------------------------------------------------------------------
Answer \ = \boxed { \boxed { x = \frac{1\pm i\sqrt{29} }{5}}}
--------------------------------------------------------------------



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Helppp pleasee ibreally need it
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-6a-5=-95  Given
-6(15)-5=-95   Substitution
a=15   idk the reason im not real good at this but i tried!
Hope you have a nice day

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