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svetlana [45]
3 years ago
14

suppose the students who scored 85 and 90 on the math test take the test again and score 95. How many stars would you have to ad

d to the picturegraph next to 95?
Mathematics
1 answer:
Ugo [173]3 years ago
5 0
Suppose the students who scored 85 and 90 on the math test take the test again and score 95. How many stars would you have to add to the picturegraph next to 95?
10
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I am Lyosha [343]

Answer:

The formula to find the radius is diameter/pie. Also, it does not show the formula that they are asking.

Step-by-step explanation:

8 0
3 years ago
Simplify 6|-3|-4|5| <br><br> Show Work
kvv77 [185]
Problem:  6|-3|-4|5|
Whenever something is in: |21| in the lines, you would just count the number itself.
So it is: 6·3-4·5 which would equal: 6·3-4·5
The answer to 6·3 is 18, so its 18 minus the answer of 5·4 which is 20.
So its: 18-20= -2
~Hope i helped. :)
6 0
3 years ago
Read 2 more answers
Hree people play a game in which one person loses and two people win each round. The loser must pay each winner the amount that
ipn [44]

Answer:

$7 ; $4 ; $3

Step-by-step explanation:

Given that:

1 player loses and 2 wins

Loser pays each winner amount each winner already has

3 rounds was played

At the end, each player has lost 1 round each and has $8.00

Since each player lost 1 round each, then each player won twice.

Given that the players are A, B and C

Starting from the last round :

Recall; they all have $8 after the last round.

If A lost the last round and pays B and C the amount they already have.

B and C finally have $8, Hence amount A paid B and C = 8/2 = $4 each

Hence, at the end of 2nd round / before last round :

A has ($8 paid + $8 final) = $16

B and C each have $4

End of first round before 2nd round of game:

If B lost, and pays A and C the amount they already have ;

A finally has 16 hence, amount B pays A = 16/2 = $8

Amount B pays C = 4/2 = $2

A = $8

B = $4 + $(8 + 2) = $14

C = $2

Ist round

C will lose :

Amount C pays B = $14 / 2 = $7

Amount C pays A = $8 /2 = $4

Hence, amount C has before round 1:

$7 + $4 + $2 = $13

Hence; Before the game ;

Either of the three players have ;

$7 ; $4 and $13

6 0
2 years ago
Which equations have infinitely many solutions?
igomit [66]

Answer:

4(x - 1) = 4x - 4

3x + 6 = 3(x + 2)

Step-by-step explanation:

The first equation is

5x - 1 = 5x + 1

We simplify to get;

- 1 = 1

This is not true, therefore this equation has no solution.

The second equation is

3x - 1 = 1 - 3x

Combine like terms:

3x + 3x = 1 + 1

6x = 2

x =  \frac{1}{3}

This has a unique solution.

The 3rd equation is

7x - 2 = 2x - 7

Group similar terms:

7x - 2x =  7 + 2 \\ 5x = 9 \\ x  =  \frac{9}{5}

The 4th equation is :

4(x - 1) = 4x - 4

4x - 4= 4x - 4 \\ x = x

This is always true. The equation has infinite solution.

The 5th equation is:

3x + 6 = 3(x + 2) \\ 3x + 6 = 3x + 6 \\ x = x

This also has infinite solution

The 6th equation is

3(x - 4) = 4(x - 3) \\ 3x - 12 = 4x - 12 \\ 3x - 4x =  - 12 + 12 \\ x = 0

It has a unique solution.

8 0
3 years ago
PLZZZ I will give brainiest and 90 points PLZZZZZZ question 6 is soo confusing plzzz
inn [45]

Answer:

simple its 16

Step-by-step explanation:

4 0
2 years ago
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