Answer: Option d.
Step-by-step explanation:
To find the domain of the function we should look for the values for which the denominator is equal to zero, because the division by zero is not allowed.
We know by definition that the function 
is always greater than zero for all <em>x</em>.
We know that the constant <em>c</em> is greater than zero (c>0).
Then, the expression 
is never equal to zero.
Therefore, it does not exist a value for <em>x</em> that makes the denominator 0. Then, the domain of the function is all real numbers.
The answer is the option d.
Answer:
Yes
Domain: 1, -1, 0, -3, 3
Range: 1, -1, 6
Step-by-step explanation:
The domain is in the left oval, the range is in the right oval. To find if its a function you have to make sure the domain (left side) doesn't "cheat". One number in the domain cant have more than one number in the range (right side), BUT (for future reference) the range can cheat. As shown, the right side numbers 1 and 6 have two different arrow pointed at them. As long as the domain doesnt "cheat" it is a function
50% is the answer im just adding words now so it will go in
Answer:
uh 14
Step-by-step explanation:
i did really just add 12+2
hope it help :)
At th x-intercept y=o
∴40x + 70 = 0
40x = -70
x = -70/40
x = -1.75
x intercepr = (-1.75,0)
