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3 years ago

Line all is bisecting segment AC. Find AC when AB = 6x - 7 and BC = 2x + 3

Mathematics

1 answer:

marin [14]3 years ago

3 0

Answer:

AC = 8x - 4

Step-by-step explanation:

AC = AB + BC

AC = 6x - 7 + 2x + 3

AC = 6x + 2x - 7 + 3

AC = 8x - 4

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In a purely monopolistic market with a demand curve P = -Q / 10 + 2000, to maximize profit the firm provides the application at

Rudiy27

Answer: hello your question lacks some data hence I will be making an assumption to help resolve the problem within the scope of the question

answer:

≈ 95 units ( output level )

Step-by-step explanation:

Given data :

P = 2000 - Q/10

TC = 2Q^2 + 10Q + 200 ( assumed value )

<u>The output level where a purely monopolistic market will maximize profit</u>

P = 2000 - Q/10 ------ ( 1 )

PQ = 2000Q - Q^2 / 10 ( aka TR )

MR = d (TR ) / dQ = 2000 - 2Q/10 = 2000 - Q/5

TC = 2Q^2 + 10Q + 200 ---- ( 2 )

MC = d (TC) / dQ = 4Q + 10

equating MR = MC

2000 - Q/5 = 4Q + 10

2000 - 10 = 4Q + Q/5

1990 = 20Q + Q

∴ Q = 1990 / 21 = 94.76 ≈ 95 units ( output level )

7 0

2 years ago

Their can u please solve.

Bingel [31]

Answer:

$\frac{45}{9} = 5$

4 0

3 years ago

Read 2 more answers

Hello,

oksano4ka [1.4K]

It took him 9.92 hours to complete the journey.

Step-by-step explanation:

Given,

Distance traveled = 50 miles

Distance traveled on horse = $\frac{50}{2}=25\ miles$

Distance traveled on foot = 25 miles

Speed while riding = 9 miles per hour

Distance = Speed * Time

Time while riding = $\frac{Distance}{Speed}$

Time while riding = $\frac{25}{9}=2.78\ hours$

Speed while waling = 3.5 miles

Time = $\frac{25}{3.5}=7.14\ hours$

Total time = 2.78+7.14 = 9.92 hours

It took him 9.92 hours to complete the journey.

Keywords: speed, distance

Learn more about distance at:

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3 years ago

What is the value of x in the equation 3x-1/9y=10, when y=27

STALIN [3.7K]

Answer: 15

Step-by-step explanation: explation in pic

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3 years ago

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Can someone please help me with this?

ddd [48]

Answer:

Step-by-step explanation:

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3 years ago