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2 years ago

Jose found a beach ball in his garage. He wants to know how much plastic was used to

Mathematics

1 answer:

Serjik [45]2 years ago

4 0

Answer:

about 616 in²

Step-by-step explanation:

The area of a sphere is given by ...

A = πd²

For a ball 14 inches in diameter, the area is ...

A = π(14 in)² = 196π in²

A ≈ 616 in²

The area of the required plastic is about 616 square inches.

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. Caroline had 400 stamps in her collection. 1 10 th of them were Indian stamps, Onethird of the remaining stamps were from Euro

Ganezh [65]

Answer:

So 400 stamps

African---> 100

Indian------> 1/10 x 400

= 40

European---> 400-40=360

1/3 x 360

= 120

so 120+40+100= 260

400-260

= 140 stams from US

6 0

3 years ago

Help please I'm stuck show and explain your work

Deffense [45]

The expressions D, E, and F represent a correct solution to the equation.

Step-by-step explanation:

Step 1:

First, we need to solve the given equation and find the value of x which satisfies the equation.

$6(x+4)=20, (x+4) = \frac{20}{6} = 3.333,$

$x = 3.333 - 4 = -0.666.$

So the value of x for the given equation is -0.666.

Step 2:

Now we evaluate the values of the six given options to see which ones have an x value of -0.666.

A. $\frac{20-4}{6}= \frac{16}{6} = 2.666,$

B. $\frac{1}{6} (20-4)= \frac{1}{6} (16)=\frac{16}{6} = 2.666,$

C. 20 -6 -4 = 20 - 10 = 10.

D. $\frac{20}{6} -4= 3.333 - 4 = -0.666,$

E. $\frac{1}{6} (20-24) = \frac{1}{6} (-4)= -0.666,$

F. $(20-24)\frac{1}{6} = (-4)\frac{1}{6} = -0.666.$

So the options D, E, and F represent a correct solution to the given equation.

7 0

3 years ago

Select the correct answer.

Kisachek [45]

This answer is c (x-4)(x+4)

6 0

2 years ago

Desiree went to the store to buy potatoes. She noticed a sign that said that she could get 3 for $1.05. How much would it cost h

iren [92.7K]

Answer:

$2.80

Step-by-step explanation:

1.05/3 =0.35 price per unit

0.35*8

$2.80

3 0

2 years ago

Read 2 more answers

If K = (AB)/(A+B) , then B = ?

marysya [2.9K]

Lets do

$\\ \sf\longmapsto K=\dfrac{AB}{A+B}$

$\\ \sf\longmapsto \dfrac{1}{K}=\dfrac{A+B}{AB}$

$\\ \sf\longmapsto \dfrac{1}{K}=\dfrac{1}{A}+\dfrac{1}{B}$

$\\ \sf\longmapsto \dfrac{1}{B}=\dfrac{1}{K}-\dfrac{1}{A}$

$\\ \sf\longmapsto \dfrac{1}{B}=\dfrac{K-A}{AK}$

$\\ \sf\longmapsto B=\dfrac{AK}{K-A}$

6 0

2 years ago