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Dovator [93]
4 years ago
14

If the radius of a circle is 11 cm, what is the area of the circle?

Mathematics
1 answer:
otez555 [7]4 years ago
5 0
Area of a circle equals πr^2, so
A = 3.14(<span>11^2)
3.14(121) = 379.94, rounded to 380.
Divide 379.94/</span>π equals 121.

Your answer is B.
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(Area of Composite Figures)Help me pls.
oksian1 [2.3K]

Answer:

69 centimeters squared

Step-by-step explanation:

First, find the area of the big square = 11cm * 4cm = 44cm

Next, find the area of the leftover square = 5cm * 5cm =25cm

Add them together to get 69 centimeters squared

Hopefully this helps - let me know if you have any questions!

6 0
3 years ago
Read 2 more answers
20 points help plz.
Andrews [41]
This area is equal to the sum of a circle with a radius of 5/2 in and a rectangle 5 by 15 in so:

A=πr^2+xy

A=π(2.5)^2+5*15

A=6.25π+75 in^2

A≈94.63 in^2  (to nearest hundredth) so

A≈95 in^2 (to nearest whole square inch)
8 0
3 years ago
Sweet tea purchased a new pair of jeans to wear to the battle of the bands on sale at 40% off he saved $20 what was the regular
DIA [1.3K]
$50 
20 x 2 = 40, which is 80% 
and then 20 divided by 2 is 10; so you add that to 40 and you get your answer 
8 0
3 years ago
A teacher asked the class to solve the equation 3(times+2)= 21 Robert wrote 3 times + 6=21 as his first step. Which property did
suter [353]
He used 3 distributive property :)
3 0
3 years ago
A person is watching a boat from the top of a lighthouse. The boat is approaching the lighthouse directly. When first noticed, t
7nadin3 [17]

To solve this problem, we can use the tan function to find for the distances covered.

tan θ = o / a

Where,

θ = angle = 90° - angle of depression

o = side opposite to the angle = distance of boat from lighthouse

a = side adjacent to the angle = height of lighthouse = 200 ft

When the angle of depression is 16°18', the initial distance from the lighthouse is:

o = 200 tan (90° - 16°18')

o = 683.95 ft

When the angle of depression is 48°51', the final distance from the lighthouse is:

o = 200 tan (90° - 48°51')

o = 174.78 ft

 

Therefore the total distance the boat travelled is:

d = 683.95 ft - 174.78 ft

<span>d = 509.17 ft</span>

4 0
3 years ago
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