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GrogVix [38]
3 years ago
15

What is the differance look at the link

Mathematics
1 answer:
Luba_88 [7]3 years ago
7 0

Answer:

The difference is \frac{3}{4} inches.

Step-by-step explanation:

See the attached number line where the worm lengths in inches are plotted.

From the number line plotted in the attached photo, it is clear that the shortest worm has the length of \frac{3}{4} inches and the longest worm has the length of 1\frac{1}{2} inches i.e. \frac{3}{2} inches.

Therefore, the difference in length between the shortest and longest worm is (\frac{3}{2} - \frac{3}{4}) = \frac{3}{4} inches. (Answer)

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Answer:

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Step-by-step explanation:

x(x^2-5x-6)

x(x-6)(x+1)

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Items produced by a manufacturing process are supposed to weigh 90 grams. The manufacturing procon
Annette [7]

Using the normal distribution, it is found that 0.26% of the items will either  weigh less than 87 grams or more than  93 grams.

In a <em>normal distribution</em> with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

  • It measures how many standard deviations the measure is from the mean.  
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In this problem:

  • The mean is of 90 grams, hence \mu = 90.
  • The standard deviation is of 1 gram, hence \sigma = 1.

We want to find the probability of an item <u>differing more than 3 grams from the mean</u>, hence:

Z = \frac{X - \mu}{\sigma}

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The probability is P(|Z| > 3), which is 2 multiplied by the p-value of Z = -3.

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2 x 0.0013 = 0.0026

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0.26% of the items will either  weigh less than 87 grams or more than  93 grams.

For more on the normal distribution, you can check brainly.com/question/24663213

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2 years ago
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Studentka2010 [4]

Answer:

It's going to be B and E because it's in the hundreds place not in the tens or whole

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2 years ago
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