All categories

2 years ago

The equation below has infinitely many solutions. -53 + 2 + 2x + 4 = ax + b True False

Mathematics

2 answers:

mash [69]2 years ago

7 0

Answer:

definatly not infinitely it should be only one correct answer so false

Step-by-step explanation:

fgiga [73]2 years ago

4 0

Answer:

False

Step-by-step explanation:

-53 + 2+ 2x + 4 = ax + b

-47 + 2x = ax + b

Since there is 3 variables you need 3 equations which you don't have. After simplifying there is nothing else you can do.

You might be interested in

Johnny is reading a novel for the read-a- Thon. The ratio of the number of pages she read to the pages that remain to be read is

mart [117]

There are several ways to answer this question and I will use this approach. Since Johnny reads at a ratio of 7:3 it can be stated that for every 10 pages in a book containing 500 pages Johnny will read 7 of those pages. There are 50 groups of 10 in a 500-page book (50 x 10). Take the ration 7:3 times 50 and use the distributive property: 7:3(50) = (7 x 50):(3 x 50) = 350:150. Based on this Johnny has read 350 pages and has 150 pages remaining.

7 0

3 years ago

Sasha buys two ribbons of equal length. She cuts 9 pieces of the same length, L, from the first ribbon and finds that 5 inches a

nikitadnepr [17]

Answer:

50 inches.

Step-by-step explanation:

Let the length of the each ribbon was x.

Now, she cuts 9 pieces of same length L which means total length is 9L.

Now, doing the same she was left with 5 inches of ribbon. Hence, we have

[tex[9L+5=x.....(1)[/tex]

Similarly, we can write a equation for the second situation.

$2L+40=x......(2)$

From equation 1 and 2,

$9L+5=2L+40\\\\7L=35\\\\L=5$

Plugging this value in equation 1,

$9(5)+5=x\\\\x=45+5\\x=50$

Therefore, the length of each ribbon when she bought them was 50 inches.

3 0

3 years ago

Use Lagrange multipliers to find the maximum and minimum values of

marusya05 [52]

The Lagrangian is

$L(x,y,\lambda)=x+8y+\lambda(x^2+y^2-4)$

It has critical points where the first order derivatives vanish:

$L_x=1+2\lambda x=0\implies\lambda=-\dfrac1{2x}$

$L_y=8+2\lambda y=0\implies\lambda=-\dfrac4y$

$L_\lambda=x^2+y^2-4=0$

From the first two equations we get

$-\dfrac1{2x}=-\dfrac4y\implies y=8x$

Then

$x^2+y^2=65x^2=4\implies x=\pm\dfrac2{\sqrt{65}}\implies y=\pm\dfrac{16}{\sqrt{65}}$

At these critical points, we have

$f\left(\dfrac2{\sqrt{65}},\dfrac{16}{\sqrt{65}}\right)=2\sqrt{65}\approx16.125$ (maximum)

$f\left(-\dfrac2{\sqrt{65}},-\dfrac{16}{\sqrt{65}}\right)=-2\sqrt{65}\approx-16.125$ (minimum)

5 0

3 years ago

I need help with this question

zhuklara [117]

4 times 3.14 times 8 squared
803.8

7 0

3 years ago

The Rachel’s daily expenses for 10 days are in the table.

Annette [7]

The correct answer is $44.20.
If we add up all the tips, the total is $442. If we divide this by the number of days (10), then we find the mean.
442 / 10 = 44.2

4 0

3 years ago