10%of 710 is 71
now we have 710-71=639
A jar of jelly beans contains 50 red gumballs , 45 yellow gumballs, and 30 green gumballs. You reach into the jar and randomly
select a jelly bean, then select another without
putting the first jelly bean back. What is the
probability that you draw two red jelly beans? This is Dependent because you didnt put the other jelly bean in thus changing the total nmber of jelly beans.
A jar of jelly beans contains 50 red gumballs<span> , 45 yellow gumballs, and 30 green gumballs. You reach into the jar and randomly select a jelly bean, then select another while replacing the first jelly bean back. What is the probability that you draw two red jelly beans? This is Independent because you put the other jelly bean in thus keeping the total number of jelly beans.</span>
Answer:
2×2×3×7
Step-by-step explanation:
84 is even, so divisible by 2. 84 = 2×42
42 is even, so divisible by 2. 82 = 2×2×21
21 has a sum of digits of 3, so is divisible by 3. 84 = 2×2×3×7
The answer is 4480 hope it helps
