If PQ=7 and QR=10, then PR=
2 answers:
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Answer:
D.
Step-by-step explanation:
We are given that,
The graph of the system of equations is a 'quadratic graph opening down and a quadratic graph opening up'.
This means that one quadratic equation will have leading co-efficient positive and other will have leading co-efficient negative.
So, we get that options A and B are discarded.
Further it is provided that the graph intersect at ( 0,3 ) and ( 2,-5 ).
This means that the pair of points must satisfy the given system of equations.
So, according to the options:
C.
Putting x = 0, gives 3 = -3, which is not possible.
So, option C is dicarded.
D.
Putting x = 0 gives 3 = 3 and x = 2 gives -5 = -5.
Hence, the graph of the given system solves the equation .