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tresset_1 [31]
4 years ago
15

Which phrase describes a scientific law?

Chemistry
1 answer:
Anit [1.1K]4 years ago
6 0

Answer:

In general, a scientific law is the description of an observed phenomenon. It doesn't explain why the phenomenon exists or what causes it. The explanation of a phenomenon is called a scientific theory. It is a misconception that theories turn into laws with enough research.

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Witch of these animals was unable to adapt to a warmer climate
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What  are the animals to choose from?

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3 years ago
How do the muscular and skeletal systems work together to allow us to move?
BlackZzzverrR [31]
I would say it is B because when u pull ur leg up the space in your muscles are smaller when you spread your leg out they relax because they are not pulling anything.<span />
7 0
3 years ago
How many protons, electrons, and neutrons does an atom with an atomic
Mkey [24]

Answer:

Protons: 50

Neutrons: 70

Electrons: 50

Explanation:

7 0
3 years ago
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Air containing 0.06% carbon dioxide is pumped into a room whose volume is 12,000 ft3. The air is pumped in at a rate of 3,000 ft
castortr0y [4]

Answer:

A(t)=1.8+34.2*e^{-t}

Explanation:

The concentration of CO2 in the room will be the amount of CO2 in the room at time t, divided by the volume of the room.

Let A(t) be the amount of CO2 in the room, in ft3 CO2.

The air entering the room is 3000 ft3/min with 0.06% concentrarion of CO2. That can be expressed as (3000*0.06/100)=1.8 ft3 CO2/min.

The mixture leaves at 3000 ft3/min but with concentration A(t)/V. We can express the amount of CO2 leaving the room at any time is A(t).

We can write this as a differential equation

dA/dt=v_i-v_o=1.8-A

We can rearrange and integrate

dA/dt=v_i-v_o=1.8-A\\\\dA/(A-1.8)=-dt\\\\\int(dA/(A-1.8) = -\int dt\\\\ln(A-1.8)=-t+C\\\\A-1.8=e^{-t}* e^{C}=C*e^{-t}\\\\A=1.8+C*e^{-t}

We also know that A(0) = 12000*(0.3/100)=36 ft3 CO2.

A(0)=1.8+C*e^{-0}\\36=1.8+C*1\\C=34.2

Then we have the amount A(t) as

A(t)=1.8+34.2*e^{-t}

5 0
3 years ago
In the laboratory, a general chemistry student measured the pH of a 0.329 M aqueous solution of benzoic acid, C6H5COOH to be 2.3
Nesterboy [21]

Answer:

The dissociation constant for the acid ( experimental ) is 1.45 lit/mol

Explanation:

The value of dissociation constant can be calculated as,

  K_{a} = C × ∝²

Where, C = concentration of the solution = 0.329M

          ∝ = Degree of dissociation

again , Degree of dissociation can be obtained form :

                      p_{H} = C × ∝

                         ∝ = \frac{p_{H} }{C}

                        ∝ = \frac{2.327}{0.329} = 7.072

So, now K_{a} = C × ∝²

                     = 0.329 ×( 7.072)²

                     = 1.45 lit/ mol

8 0
4 years ago
Read 2 more answers
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