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Dima020 [189]
3 years ago
12

What will be the starting roster for this upcoming game

Mathematics
1 answer:
MArishka [77]3 years ago
8 0
LeBron, Alex, kuz, Howard, green
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Mr. Wilson has $3,000 in his bank account. Ms. Nelson has 10 times as much money in her bank account as Mr. Wilson has in his ba
laiz [17]

Since Mr. Wilson has $3,000 and Ms. Nelson has 10 times more than that, we can set up a basic equation determining how much money Ms. Nelson has.

(10)(3000)=30000

Ms. Nelson has $30,000 while Mr. Wilson has only $3,000.

8 0
3 years ago
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Maria bought five shirts and spent a total of $34.25. How much did one shirt cost if all of the shirts cost the same? *We know t
Tatiana [17]

Answer:

Maria bought five shirts and spent a total of $34.25. How much did one shirt cost if all of the shirts cost the same? *We know the price of 5, how do we find the price of 1? ( PLS HELP MEEEEEEE I HAVE MORE WORK TOO

3 0
3 years ago
Can someone answer this questions?<br><br>also, is 10^5 the same as 1/10^5??
Yuri [45]

\bf \textit{volume of a sphere}\\\\ V=\cfrac{4\pi r^3}{3}~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ r=3\cdot 10^2 \end{cases}\implies V=\cfrac{4\pi (3\cdot 10^2)^3}{3} \implies  V=\cfrac{4\pi (3^3\cdot 10^{2\cdot 3})}{3} \\\\\\ V=4\pi (3^3\cdot 10^6)3^{-1}\implies V=4\pi 3^33^{-1}\cdot 10^6\implies V=4\pi 3^{3-1}10^6 \\\\\\ V=4\cdot \pi \cdot 3^2\cdot 10^6

6 0
3 years ago
Given a function I and a subset A of its domain, let I(A) represent the range of lover the set A; that is, I(A) = {I(x) : x E A}
Ede4ka [16]

Step-by-step explanation:

(a)

Using the definition given from the problem

f(A) = \{x^2  \, : \, x \in [0,2]\} = [0,4]\\f(B) = \{x^2  \, : \, x \in [1,4]\} = [1,16]\\f(A) \cap f(B) = [1,4]  = f(A \cap B)\\

Therefore it is true for intersection. Now for union, we have that

A \cup B = [0,4]\\f(A\cup B ) = [0,16]\\f(A) = [0,4]\\f(B)= [1,16]\\f(A) \cup f(B) = [0,16]

Therefore, for this case, it would be true that f(A\cup B) = f(A)\cup f(B).

(b)

1 is not a set.

(c)

To begin with  

A\cap B \subset A,B

Therefore

g(A\cap B) \subset g(A) \cap g(B)

Now, given an element of g(A) \cap g(B) it will belong to both sets, therefore it also belongs to g(A\cap B), and you would have that

g(A)\cap g(B) \subset  g(A \cap B), therefore  g(A)\cap g(B)  =  g(A \cap B).

(d)

To begin with A,B  \subset A \cup B, therefore

g(A) \cup g(b) \subset g(A\cup B)

7 0
4 years ago
Find f(6) if f(x)=x to the second power ÷3+x
Maslowich

f(x)=\dfrac{x^2}{3+x}\\\\f(6)=\dfrac{6^2}{3+6}=\dfrac{36}{9}=4

6 0
3 years ago
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