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just olya [345]
3 years ago
15

The length of one side, s, of a shipping box is s(x) = ^3√2x, where x is the volume of the box in cubic inches. A manufacturer n

eeds the volume of the box to be between 108 in.3 and 256 in.3. What are the minimum and maximum possible lengths of s?
Mathematics
1 answer:
almond37 [142]3 years ago
8 0

Answer:

Minimum value: 6 inches,

Maximum value: 8 inches.

Step-by-step explanation:

To find the minimum length of s, we need to use the minimum volume of the shipping box in the equation, so:

s_minimum = ^3√(2*108) = ^3√216 = 6 inches

The maximum value of the volume will give us the maximum value of the length:

s_maximum = ^3√(2*256) = ^3√512 = 8 inches

So the minimum value of the length is 6 inches and the maximum value is 8 inches.

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We first write the fractions in their decimal forms and find out the ratio.

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What is the equation of this line in slope-intercept form?
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Step-by-step explanation:

From the graph, you see the line intersects the y-axis at y = 2, so the y-intercept is b = 2.

Now we need the slope. We need to find the number of vertical and horizontal units to go from one point to the other. Starting at point (-1, 5), go down 6 units and then go right 2 units. The change in y is -6. The change in x is 2. slope = m = (change in y)/(change in x) = -6/2 = -3.

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4 0
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Margarita [4]

Answer:

A) 15x - 12

General Formulas and Concepts:

<u>Pre-Algebra</u>

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Step-by-step explanation:

<u>Step 1: Define</u>

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