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sergiy2304 [10]
3 years ago
12

Between nitromethane (CH3-NO2) and methyl nitrite (CH3-0-NO), which has the higher boiling point? Explain the reason in less tha

n 90 words.
Chemistry
1 answer:
kondor19780726 [428]3 years ago
7 0

Answer:

CH_3NO_2 has higher boiling point

Explanation:

CH_3NO_2 has higher boiling point because in CH_3NO_2 , NO_2  has a very strong dipole and we know that whenever there is dipole-dipole interaction then boiling point increases. On the other hand in CH_3-O-NO the NO group has not so strong dipole which weakens its boiling point

So the boiling point of CH_3NO_2 is higher than the boiling point of  CH_3-O-NO

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2. How many moles of fluorine are required to produce 12.0 grams of
LuckyWell [14K]

Answer:

0.0984mol of F2

Explanation:

The equation for the reaction is given below:

Kr + F2 → KrF2

Let us convert 12g of KrF2 to mole. This is illustrated below

Molar Mass of KrF2 = 84 + (2x19) = 84 + 38 = 122g/mol

Mass of KrF2 = 12g

Number of mole = Mass /Molar Mass

Number of mole of KrF2 = 12/122 = 0.0984mol

From the equation,

1mole of F2 produced 1mole of KrF2.

Therefore 0.0984mol of F2 will produce 0.0984mol of KrF2

7 0
3 years ago
Can somebody please help me
kramer

Answer:

a) carboxylic acid

b) amine

c) ester

d) aldehyde

e) alkene

f) ketone

Explanation:

Most of them are straight forward.

4 0
3 years ago
The proton has a mass of?
aliina [53]
The relative mass is 1
3 0
3 years ago
While performing the assays for the LDH kinetics experiment, you will pipet 25ul of 250 ug/ml LDH into 975 ul of assay buffer (T
ArbitrLikvidat [17]

Answer:

6.25 μg/mL

Explanation:

When a dilution is made, the mass of the solute is conserved (Lavoiser's law), so the mass pipetted will be the mass in the assay. The mass is the concentration (C) multiplied by the volume (V). If the pipet solution is called 1, and the assay 2:

m1 = m2

C1*V1 = C2*V2

C1 = 250 μg/mL

V1 = 25 μL

V2 = 975 μL + 25 μL = 1000 μL (is the final volume of the assay after the addition of LDH)

250*25 = C2*1000

C2 = 6.25 μg/mL

6 0
3 years ago
A beaker with 1.60×102 mL of an acetic acid buffer with a pH of 5.000 is sitting on a benchtop. The total molarity of acid and c
stich3 [128]

Answer:

The pH will change 0.16 ( from 5.00 to 4.84)

Explanation:

Step 1: Data given

volume of acetic acid buffer = 160 mL

The total molarity of acid and conjugate base in this buffer is 0.100 M

A student adds 7.10 mL of a 0.460 M HCl solution to the beaker.

The pKa of acetic acid is 4.740

pH = 5.00

Step 2: Calculate concentration of acid

Consider x = concentration acid

Consider y = concentration conjugate base

x + y = 0.100

5.00 = 4.740 + log y/x

5.00 - 4.740 = log y/x

0.26 = log y/x

10^0.26 =1.82 = y/x

1.82 x = y

Since x+y = 0.100

x + 1.82 x = 0.100

2.82 x = 0.100

x =0.0355 M = concentration acid

Step 3: Calculate concentration of conjugate base

y = 0.100 - x

0.100 - 0.0355 =0.0645 M= concentration conjugate base

Step 4: Calculate moles of acid

Moles = volume * molarity

moles acid = 0.160 L * 0.0355 M= 0.00568  moles

Step 5: Calculate moles of conjugate base

moles conjugate base = 0.0645 M * 0.160 L=0.01032 moles

Step 6: Calculate moles HCl

moles HCl = 7.10 * 10^-3 L * 0.460 M=0.003266 moles

Step 7: Calculate new moles

A- + H+ = HA

moles conjugate base = 0.01032 - 0.003266 =0.007054  moles

moles acid = 0.00568 + 0.003266=0.008946 moles

Step 8: Calculate the total volume

total volume = 160 + 7.10 = 167.1 mL = 0.1671 L

Step 9: Calculate the concentration of the acid

concentration acid = 0.008946/ 0.1671 =0.0535 M

Step 10: Calculate the concentration of conjugate base

concentration conjugate base = 0.007054/ 0.1671 =0.0422 M

Step 11: Calculate the pH

pH = 4.740 + log 0.0535/ 0.0422=4.84

change pH = 5.00 - 4.84=0.16

The pH will change 0.16

5 0
3 years ago
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