287.2L
Explanation:
Given parameters:
Mass of sodium peroxide = 1000g = 1kg
Unknown
volume of oxygen produced at STP
Solution:
At standard temperatue and pressure STP;
Number of moles = 
molar mass of Na₂O₂ = (2 x 23) + (2 x 16 ) = 78g/mol
Number of moles =
= 12.82mole
To solve this problem, we need to write the equation of the reaction since this is a decomposition reaction;
Na₂O₂ → 2Na + O₂
The unknown is the volume of oxygen that would be produced at STP
Volume of gas at STP = number of moles x 22.4
From the equation;
1 mole of Na₂O₂ produced 1 mole of O₂ gas
12.82mole will produce 12.82mole of oxygen gas
Now, the volume of gas at STP = 12.82 x 22.4 = 287.2L
learn more:
Volume of gas at STP brainly.com/question/12684384
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