1kg of sodium per oxide will produce what quantity of oxygen in STP
1 answer:
287.2L
Explanation:
Given parameters:
Mass of sodium peroxide = 1000g = 1kg
Unknown
volume of oxygen produced at STP
Solution:
At standard temperatue and pressure STP;
Number of moles =
molar mass of Na₂O₂ = (2 x 23) + (2 x 16 ) = 78g/mol
Number of moles = = 12.82mole
To solve this problem, we need to write the equation of the reaction since this is a decomposition reaction;
Na₂O₂ → 2Na + O₂
The unknown is the volume of oxygen that would be produced at STP
Volume of gas at STP = number of moles x 22.4
From the equation;
1 mole of Na₂O₂ produced 1 mole of O₂ gas
12.82mole will produce 12.82mole of oxygen gas
Now, the volume of gas at STP = 12.82 x 22.4 = 287.2L
learn more:
Volume of gas at STP brainly.com/question/12684384
#learnwithBrainly
You might be interested in
Answer: The boiling point of water at 81 kPa will be 298.17 K.
Explanation:
The boiling point of water is 373 K at atmospheric pressure. So, to calculate the boiling point at 81 kPa, we use the law given by Gay-Lussac.
Gay-Lussac Law states that pressure is directly proportional to the temperature when volume and moles remain constant.
Mathematically,
where,
= Initial pressure and temperature
= Final pressure and temperature
We are given:
Putting values in above equation, we get:
Hence, the boiling point of water at 81 kPa will be 298.17 K.
Answer: 15.0 moles of are formed from 30.0 mol of
Explanation:
The balanced chemical reaction is :
According to stoichiometry :
2 moles of give = 1 mole of
Thus 30.0 moles of will give =
of
Thus 15.0 moles of are formed from 30.0 mol of