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1 answer:
Answer:
slope of EF=
∠QSR=45°,
∠PTQ=90°
if RT=24
then SQ=48
square is always a rectangle
∠SUT=21°
Step-by-step explanation:
two line are perpendicular to each other if product of their slope equal to -1
=-1
slope of HE==-
slope of EF=
slope of EF=-1=
slope of EF= answer
∠QSR=45°,
∠PTQ=90°
if RT=24
then SQ=48
square is always a rectangle
given ∠SUT=3x+6
∠RUS=5x-4
∠SUT=∠RUS
3x+6=5x-4
x=5
∠SUT=3x+6=15+6=21°
∠SUT=21°
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Answer:
see below
Step-by-step explanation:
The mapping tells you how to find the vertices of the image:
(x, y) ⇒ (x +2, y -3)
S(-3,-2) ⇒ S'(-3 +2, -2 -3) = S'(-1, -5) . . . . . matches choice D
T(-4, 3) ⇒ T'(-4 +2, 3 -3) = T'(-2, 0)
V(-2, 3) ⇒ V'(-2 +2, 3 -3) = V'(0, 0)
Answer:
11700 mm²
Step-by-step explanation:
A rectangle is a quadrilateral with two equal, opposite and parallel sides. Each of the angles in a rectangle is 90°.
The horizontal distance of the rectangle = r + r + r + r = 4r
The vertical distance = r + h + r = 2r + h
Where h is the distance between the midpoint of the 2 up circles and the midpoint of the down circle.
Using Pythagoras:
(2r)² = h² + r²
h² + r² = 4r²
h² = 3r²
h = √3r²
h = r√3
Vertical distance = 2r + h = 2r + r√3
Area of rectangle = vertical distance * horizontal distance
Area = 4r * (2r + r√3) = 8r² + 4r²√3 = 4r²(2 + √3)
Substituting:
Area = 4r²(2 + √3) = 4(28²)(2 + √3) = 11703.711 mm²
Area = 11700 mm² to 3 s.f
