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Taya2010 [7]
3 years ago
8

A builder is buying property to build new houses. The sizes of the lots are 1 2 , 1 3 , 1 6 , 1 2 , 1 6 , 1 2 , 1 6 , 1 2 , 1 3

, 1 2 , 1 6 , 1 6 , 1 6 , 1 2 , and 1 3 acre. Select the line plot that represents the information.
Mathematics
1 answer:
Genrish500 [490]3 years ago
3 0

Answer:

The line plot should have 6 dots on the 12 tick mark, 2 on 13, and 6 on 16.

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trapecia [35]
I would say two is the right one
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3 years ago
What is the answer 1 plus 1
AnnZ [28]

Answer:

the answer is 4, just kidding it's 2

Step-by-step explanation:

5 0
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Math:
Dahasolnce [82]

Answer:

a) x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i, \forall i \in \mathbb{N}_{O}, x_{2} = \frac{5\pi}{6}\pm 2\pi\cdot i, \forall i \in \mathbb{N}_{O}, b) x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i, \forall i \in \mathbb{N}_{O}, x_{2} = \frac{5\pi}{3}\pm 2\pi\cdot i, \forall i \in \mathbb{N}_{O}

Step-by-step explanation:

a) The equation must be rearranged into a form with one fundamental trigonometric function first:

\sqrt{3}\cdot \csc x - 2 = 0

\sqrt{3} \cdot \left(\frac{1}{\sin x} \right) - 2 = 0

\sqrt{3} - 2\cdot \sin x = 0

\sin x = \frac{\sqrt{3}}{2}

x = \sin^{-1} \frac{\sqrt{3}}{2}

Value of x is contained in the following sets of solutions:

x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i, \forall i \in \mathbb{N}_{O}

x_{2} = \frac{5\pi}{6}\pm 2\pi\cdot i, \forall i \in \mathbb{N}_{O}

b) The equation must be simplified first:

\cos x + 1 = - \cos x

2\cdot \cos x = -1

\cos x = -\frac{1}{2}

x = \cos^{-1} \left(-\frac{1}{2} \right)

Value of x is contained in the following sets of solutions:

x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i, \forall i \in \mathbb{N}_{O}

x_{2} = \frac{5\pi}{3}\pm 2\pi\cdot i, \forall i \in \mathbb{N}_{O}

7 0
3 years ago
Which figure has two circular faces?
Vladimir79 [104]

Answer:

Figure A

Step-by-step explanation:

Hope it helps.

7 0
3 years ago
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8x2 - 6x + 3 – 2x – 10x?
Marina CMI [18]

Answer:

8x^{2} + 3 + -6x

Step-by-step explanation:

First we need to find the like terms so that we could add them. In this case the like terms are,

1. 6x , -2x , -10x

So, these are the only terms that we can add in this expression.

Hence,

=> 8x^{2} + 3 + (6x - 2x - 10x)

=> 8x^{2} + 3 + -6x

And this is as simple as this expression can go until we find the value of "x" which is not yet told.

Hope my answer helped.

4 0
3 years ago
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