I personally think that summarizing important points is the way to go!
Answer:
using namespace std;
int main()
{
float x,y;
cout<<"Enter a value of feet: ";
cin>>x;
y=x*0.305;
cout<<x<<" feet is "<<y<<" meters";
return 0;
}
Explanation:
The program is written in C++ language but the problem can be carried out in any language using the premises given here.
You have to declare your variables for feet and meters (x and y in this case). The you prompt the user via the message on screen given by the cout word and the << sign, and the value read via the cin word and the >> sign and stored into x. Then you multiply x by 0.305 and store it in y, and show them on screen via cout. Note that literal words are written between " " and variables are written just like that.
The mode of interent she would be using is A. Email. Customer inquires/ Customer Service is normally provided using the mode of Email. Hope it helps!
Answer:
import java.util.Scanner;
public class num9 {
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
System.out.println("Enter three numbers between 0 and 100");
double num1 = in.nextDouble();
double num2 = in.nextDouble();
double num3 = in.nextDouble();
double min = 0;
double sMin = 0;
double tMin = 0;
if(num1<num2 && num1<num3){
min = num1;
sMin = num2;
tMin = num3;
}
else if(num2<num1 && num2<num3){
min = num2;
sMin = num1;
tMin = num3;
}
else if(num3<num2 && num3<num1){
min = num3;
sMin = num1;
tMin = num2;
}
double average = (sMin+tMin)/2;
System.out.printf("The average of the two highest scores is:%.1f \n",average);
}
}
Explanation:
- Using Java programming language. The Scanner class is used to receive the three numbers. The user is prompted to enter a valid number between 0 and 100.
- Using three IF statements the minimum (min), second largerst (sMin) and the largest (tMin) of the three numbers is determined.
- the average of the sMin and tMin is calculated and printed to the console with the printf method to one decimal place.
